All categories

3 years ago

A rectangle is formed by placing two identical squares side by side

1 answer:

7 0

The perimeter of one square is 20 cm.

explanation: since the rectangle can be divided into two squares, we can conclude that the area of one square is 25 cm^2 because 50 / 2 = 25. the square root of 25 is 5, so one side length of the square is 5 cm. multiply that by 4 (because there’s 4 sides) and you get 20 cm.

You might be interested in

Eyan bought 234 pounds of apples for $1.32 per pound, 112 pounds of peaches for $1.20 per pound, and some tomatoes, all from a g

9966 [12]

Answer:

the money spend on tomatoes is $4.20

Step-by-step explanation:

The computation of the money spend on tomatoes is shown below

Let the money spend on tomatoes be x

$2 \frac{3}{4} \times \$1.32 + 1\frac{1}{2} \times \$1.20 + x = \$9.63\\\\$

$3.63 + $1.80 + x = $9.63

x = $9.63 - $3.63 + $1.80

= $4.20

Hence, the money spend on tomatoes is $4.20

4 0

3 years ago

Michael is trying to show that ABC is congruent to A’B’C’ by showing that A’B’C’ is reflection of ABC in the x-axis

Vesna [10]

Answer:

uhh, whats the question? id like to answer :/

6 0

3 years ago

Help me find the volume of the composite figure

Butoxors [25]

Answer:

$V = 97.911in^3$

Step-by-step explanation:

Given

Shapes: Cube and Cone

Required

Determine the volume

First we calculate the volume of the cube

$V_1 = l^3$

Where

l = side length = 5.1

$V_1 = 5.1^3$

$V_1 = 132.651$

Next, calculate the volume of the cone using:

$V_2 = \frac{\pi r^2h}{3}$

Where

h = 5.1

$r = \frac{1}{2} * Diameter$

$r = \frac{1}{2} * 5.1$

$r = 2.55$

So, we have:

$V_2 = \frac{\pi r^2h}{3}$

$V_2 = \frac{\pi * 2.55^2 * 5.1}{3}$

$V_2 = \frac{22 * 2.55^2 * 5.1}{7*3}$

$V_2 = \frac{729.5805}{21}$

$V_2 = 34.74$

The volume of the figure is:

$V=V_1 - V_2$

$V_1 = 132.651$

$V = 132.651 - 34.74$

$V = 97.911in^3$

8 0

3 years ago

Math help please!<br> |120+x| x<-120

In-s [12.5K]

Answer:

-120-x

Step-by-step explanation:

Given:

$\displaystyle \large{|120+x| \quad (x < -120)}$

This is the same as previous one. Recall modulus property:

$\displaystyle \large{|a+x| = \begin{cases} a+x \quad (x \geq -a) \\ -a-x \quad (x < -a) \end{cases}}$

Keep in mind that |x+a| and |a+x| are equal via addition property.

Since the question gives interval of x < -120:

Therefore, the expression is -120-x

4 0

2 years ago

Find the solution of this system of equations<br> -2y = 48 + 6x<br> -6x + 9y = -84

anygoal [31]

-2y = 48 + 6x
-6x - 2y = 48 ——(1)

-6x + 9y = -84
-6x = -84 -9y ——(2)

Substitute (2) into (1):
(-84 -9y) -2y = 48
-84 -9y -2y = 48
-84 -11y = 48
-11y = 48 + 84
-11y = 132
y = - 12

Substitute y = -12 into (1):
-6x -2(-12) = 48
-6x + 24 = 48
-6x = 48 -24
-6x = 24
X = -4

ANS : y= -12, x= -4

4 0

2 years ago