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VMariaS [17]
4 years ago
10

Find the symmetries Y^2+4=x

Mathematics
1 answer:
Mamont248 [21]4 years ago
7 0
Hello:
<span>the symmetries : axis- x </span>

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3x-9x+6=20-3x+4x Please answer.
fomenos
I gotchu.
<span>3x-9x+6=20-3x+4x
Combine like terms.
-6x+6=20+x
Bring x over to the left side.
-x            -x
-7x+6=20
bring 6 to the right side.
     -6   -6
-7x=14
Divide -7 on both sides to isolate x.
x= -2

CHECK
</span><span>3x-9x+6=20-3x+4x
-6(-2)+6=20+(-2)
18=18 
ANSWER: x= -2</span>
6 0
3 years ago
How do you write the standard number 3,500 in scientific notation? A. 3.5 × 101 B. 3.5 × 105 C. 3.5 × 103 D. 3.5 × 104
Svet_ta [14]

Answer:

C 3.5*10^3

Step-by-step explanation:

7 0
3 years ago
3y + x = 12<br> What is the value of x when y = 3?
Andre45 [30]

Step-by-step explanation:

3y + x = 12

When y = 3, we have 3(3) + x = 12.

=> 9 + x = 12, x = 3.

6 0
3 years ago
What is the median of the followng set of number 1,6,8 and 10
erastova [34]

The answer is 2.5

Step-by-step explanation:

Formula = (N + 1 / 2th) term

So,

Total numbers (N) = 4

Now,

(N + 1 / 2th) term

= (4 + 1 / 2th) term

= (5 / 2th) term

= (2.5th) term

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3 0
3 years ago
3x+2y=6 and y=1/3x-11 perpendicular or parallel
IgorLugansk [536]

Answer: To determine if two lines are parallel or perpendicular, you have to look at the slopes. For the line y=kx+b, k is the slope.

For two lines  y=k1x+b1 and y=k2X+b2 ,When K1=K2, two lines are parallel; when K1=-1/k2, two lines are perpendicular. It doesn't matter whatever b1, b2 are. Hence to save time, you only need to calculate  k1 and k2.

To calculate the slope k of any line, you have to change the equation to y=kx+b

For -y=3x-2, k=3/(-1)=-3 (you divide -1 on each side of =, but you don't need to calculate -2/(-1))

For -6X+2y=6, K=6/2=3 (you first move the -6x to right side, it becomes 6x, then divide by 2)

Now you can get the answer: The two lines neither parallel nor perpendicular.

6 0
3 years ago
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