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3 years ago

In 10 years mike will be 3. Times his current age. What is his current age

Mathematics

2 answers:

Alexus [3.1K]3 years ago

8 0

He has to be 5 since 5×3=15 and each year he turns one year older so yea

DanielleElmas [232]3 years ago

5 0

His current age now = x

and after 10 years, it will be triple of now >> x+10 = 3x

solve for x

x+10 = 3x
x-x+10 = 3x-x
10 = 2x
5=x

so he is 5 years old now

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Ulleksa [173]

Answer:

x = 4.45 or x = - 4.45

Step-by-step explanation:

Here are the steps:

Substitute the values,

$4+\sqrt{-4^2-4(1*-2)}$ ÷ 2 × 1

x = 2 ± √6

x = 4.45 or x = - 4.45

good luck, i hope this helps :)

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3 years ago

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30 POINTS!!!! What is the value of x? 90 135 180 225

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Answer:

180 degrees.

Step-by-step explanation:

Because the angle at the circumference is 90 degrees the arc joining the 2 other points = 180 degrees.

So x = 360 - 180 = 180 degrees.

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4 years ago

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3 years ago

Find all possible values of α+

const2013 [10]

Answer:

$\rm\displaystyle 0,\pm\pi$

Step-by-step explanation:

please note that to find but α+β+γ in other words the sum of α,β and γ not α,β and γ individually so it's not an equation

===========================

we want to find all possible values of α+β+γ when tanα+tanβ+tanγ = tanαtanβtanγ to do so we can use algebra and trigonometric skills first

cancel tanγ from both sides which yields:

$\rm\displaystyle \tan( \alpha ) + \tan( \beta ) = \tan( \alpha ) \tan( \beta ) \tan( \gamma ) - \tan( \gamma )$

factor out tanγ:

$\rm\displaystyle \tan( \alpha ) + \tan( \beta ) = \tan( \gamma ) (\tan( \alpha ) \tan( \beta ) - 1)$

divide both sides by tanαtanβ-1 and that yields:

$\rm\displaystyle \tan( \gamma ) = \frac{ \tan( \alpha ) + \tan( \beta ) }{ \tan( \alpha ) \tan( \beta ) - 1}$

multiply both numerator and denominator by-1 which yields:

$\rm\displaystyle \tan( \gamma ) = - \bigg(\frac{ \tan( \alpha ) + \tan( \beta ) }{ 1 - \tan( \alpha ) \tan( \beta ) } \bigg)$

recall angle sum indentity of tan:

$\rm\displaystyle \tan( \gamma ) = - \tan( \alpha + \beta )$

let α+β be t and transform:

$\rm\displaystyle \tan( \gamma ) = - \tan( t)$

remember that tan(t)=tan(t±kπ) so

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta\pm k\pi )$

therefore when k is 1 we obtain:

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta\pm \pi )$

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$\rm\displaystyle \tan( \gamma ) = \tan( -\alpha -\beta\pm \pi )$

recall that if we have common trigonometric function in both sides then the angle must equal which yields:

$\rm\displaystyle \gamma = - \alpha - \beta \pm \pi$

isolate -α-β to left hand side and change its sign:

$\rm\displaystyle \alpha + \beta + \gamma = \boxed{ \pm \pi }$

when is 0:

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$\rm\displaystyle \tan( \gamma ) = \tan( -\alpha -\beta\pm 0 )$

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$\rm\displaystyle \gamma = - \alpha - \beta \pm 0$

isolate -α-β to left hand side and change its sign:

$\rm\displaystyle \alpha + \beta + \gamma = \boxed{ 0 }$

and we're done!

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3 years ago

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Usimov [2.4K]

Hello!

The angles are supplementary meaning they add to 180°

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3a + 3 = 180

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3a = 177

Divide both sides by 3

a = 59

the answer is 59°

Hope this helps!

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3 years ago

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