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padilas [110]
3 years ago
6

Solve the system using elimination.

Mathematics
1 answer:
vampirchik [111]3 years ago
3 0

Answer:

x = 9(4)-34 = 2

Step-by-step explanation:

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1. Solve proportion 12/15 = 18/b
omeli [17]
We solve the as follows:

<span>1. Solve proportion 12/15 = 18/b
</span>( 12/15 = 18/b ) b<span>
( 12b/15 = 18 ) 15/12
b = 18(15/12)
b = 45/2

2. Solve equations 

A. -x + 4 = x +6 
</span>-x + 4 - x = x +6 - x
<span>-2x + 4 - 4 = 6 - 4
-2x = 2
x = -1

B. 5n + 7 =7(n+1) -2n 
5n + 7 = 7n + 7 - 2n
5n -7n + 2n = 7 - 7
0 = 0

C. -4(p+2) + 8 = 2(p-1) - 7p + 15
-4p - 8 + 8 = 2p - 2 - 7p + 15
-4p + 7p - 2p = -2 + 15 + 8 - 8
p =13

3. Solve a/b x - c = 0 for x 
</span>a/b x - c = 0 
( a/b x = c ) b/a
x = bc / a
3 0
3 years ago
Futhe Mathematics<br><img src="https://tex.z-dn.net/?f=%28Cos%20%7B%7D%5E%7B4%7Dt%20-Sin%20%7B%7D%5E%7B4%7Dt%20%29%20%20%5Cdiv%2
Nastasia [14]

Answer:

cos2t/cos²t

Step-by-step explanation:

Here the given trigonometric expression to us is ,

\longrightarrow \dfrac{cos^4t - sin^4t }{cos^2t }

We can write the numerator as ,

\longrightarrow \dfrac{ (cos^2t)^2-(sin^2t)^2}{cos^2t }

Recall the identity ,

\longrightarrow (a-b)(a+b)=a^2-b^2

Using this we have ,

\longrightarrow \dfrac{(cos^2t + sin^2t)(cos^2t-sin^2t)}{cos^2t}

Again , as we know that ,

\longrightarrow sin^2\phi + cos^2\phi = 1

Therefore we can rewrite it as ,

\longrightarrow \dfrac{1(cos^2t - sin^2t)}{cos^2t}

Again using the first identity mentioned above ,

\longrightarrow \underline{\underline{\dfrac{(cost + sint )(cost - sint)}{cos^2t}}}

Or else we can also write it using ,

\longrightarrow cos2\phi = cos^2\phi - sin^2\phi

Therefore ,

\longrightarrow \underline{\underline{\dfrac{cos2t}{cos^2t}}}

And we are done !

\rule{200}{4}

Additional info :-

<em>D</em><em>e</em><em>r</em><em>i</em><em>v</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>o</em><em>f</em><em> </em><em>c</em><em>o</em><em>s</em><em>²</em><em>x</em><em> </em><em>-</em><em> </em><em>s</em><em>i</em><em>n</em><em>²</em><em>x</em><em> </em><em>=</em><em> </em><em>c</em><em>o</em><em>s</em><em>2</em><em>x</em><em> </em><em>:</em><em>-</em>

We can rewrite cos 2x as ,

\longrightarrow cos(x + x )

As we know that ,

\longrightarrow cos(y + z )= cosy.cosz -  siny.sinz

So that ,

\longrightarrow cos(x+x) = cos(x).cos(x) - sin(x)sin(x)

On simplifying,

\longrightarrow cos(x+x) = cos^2x - sin^2x

Hence,

\longrightarrow\underline{\underline{cos (2x) = cos^2x - sin^2x }}

\rule{200}{4}

7 0
2 years ago
Write down a pair of integers whose
liubo4ka [24]
<span>The pair of integers that I chose are:

(a) sum is –3
5 + (-8) = -3

(b) difference is –5
2 - 7 = -5

(c) difference is 2
14 -12 = 2

(d) sum is 0
2 - 2 = 0</span>
3 0
3 years ago
B(n)=−4−2(n−1)<br> What's the 12th term in the sequence?
marysya [2.9K]

The 12th term in the sequence is -26.

Given,

B (n) = -4 – 2(n – 1)

We have to find the 12th term in the sequence:

To find the nth term in an arithmetic sequence:

An arithmetic sequence's nth term is determined by the formula a = a + (n - 1)d. The common difference, or d, is the difference between any two consecutive terms in an arithmetic series; it can be calculated by deducting any pair of terms starting with a and an+1.

Here,

First term, a = -4

Common difference, d = -2

nth term = 12

Now, let’s find 12th term

B(n) = -4 -2(n – 1)

B(12) = -4 – 2(12 – 1)

B(12) = -4 -2(11)

B(12) = -4 -22

B(12) = -26

That is, the 12th term in the sequence is -26.

Learn more about arithmetic sequence here:

brainly.com/question/11570734

#SPJ1

8 0
1 year ago
Anthony goes to the gym for __30____ minutes on Monday. Every day he ___increases____his gym time by _____5 minutes_______. If h
Stolb23 [73]
Geometric sequence is a sequence of numbers that have a common ratio between them.
6 0
3 years ago
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