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Ira Lisetskai [31]
3 years ago
6

Each statement describes a transformation of the graph of y = x2. Which statement correctly describes the graph of y = (x + 4)2

- 7?
A.
It is the graph of y = x2 translated 4 units down and 7 units to the left.

B.
It is the graph of y = x2 translated 4 units up and 7 units to the left.

C.
It is the graph of y = x2 translated 7 units down and 4 units to the left.

D.
It is the graph of y = x2 translated 7 units down and 4 units to the right.

Mathematics
2 answers:
alina1380 [7]3 years ago
6 0
  • Vertex Form: y=(x-h)^2+k , with (h,k) as the vertex.

So the new equation is in vertex form. And looking at this equation, we see the vertex as (-4,-7) <em>(Remember that y = (x + 4)^2 - 7 can be also written as y = (x - (-4))^2 - 7).</em>

Since negative x-coordinates go to the left on the x-axis and negative y-coordinates go down on the y-axis, <u>your answer is going to be C. It is the graph of y = x^2 translated 7 units down and 4 units to the left.</u>

nataly862011 [7]3 years ago
5 0

It is the graph of y = x² translated 7 units down and 4 units to the left.

<h3>Further explanation</h3>

There are four types of transformation geometry:

  • translation (or shifting),
  • reflection,
  • rotation, and
  • dilation (stretching or shrinking).  

In this case, the transformation is shifting vertically and horizontally.

  • Translation (or shifting): moving a graph on an analytic plane without changing its shape.  
  • Vertical shift: moving a graph upwards or downwards without changing its shape.  
  • Horizontal shift: moving a graph to the left or right downwards without changing its shape.  

Vertical Shift

Given the graph of y = f(x) and v > 0, we obtain the graph of:  

  • \boxed{ \ y = f(x) + v \ } by shifting the graph of \boxed{ \ y = f(x) \ } upward v units.
  • \boxed{ \ y = f(x) - v \ } by shifting the graph of \boxed{ \ y = f(x) \ } downward v units.  

Horizontal Shift

Given the graph of y = f(x) and h > 0, we obtain the graph of:  

  • \boxed{ \ y = f(x + h) \ } by shifting the graph of \boxed{ \ y = f(x) \ } to the left h units.  
  • \boxed{ \ y = f(x - h) \ } by shifting the graph of \boxed{ \ y = f(x) \ } to the right h units.

- - - - - - - - - -

<u>Given:</u>

\boxed{ \ y = x^2 \rightarrow \ ? \rightarrow  \ y = (x + 4)^2 - 7 \ }

Clearly, to obtain the graph of \boxed{ \ y = (x + 4)^2 - 7 \ } we must translate the graph of \boxed{ \ y = x^2 \ }.

  • \boxed{ \ y = x^2 \ } translated 7 units down.
  • It becomes \boxed{ \ y = x^2 - 7 \ }
  • Furthermore, \boxed{ \ y = x^2 - 7 \ } translated 4 units to the left.

Thus, the result is \boxed{ \ y = (x + 4)^2 - 7 \ }

<u>Conclusion</u>

The statement correctly describes the graph of y = (x + 4)² - 7 is the graph of y = x² translated 7 units down and 4 units to the left.

The answer is C.

<h3>Learn more  </h3>
  1. Transformations that change the graph of f(x) to the graph of g(x) brainly.com/question/2415963
  2. The similar problem brainly.com/question/1369568
  3. Which equation represents the new graph brainly.com/question/2527724

Keywords: each statement, describes, a transformation, the graph, y = x², which, correctly, y = (x + 4)² - 7, translation, shifting, left, down, upward, units, up,  horizontal, vertical

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6 0
3 years ago
Read 2 more answers
Suppose that we don't have a formula for g(x) but we know that g(3) = −5 and g'(x) = x2 + 7 for all x.
Leni [432]

Answer:

a)

g(2.9) \approx -6.6

g(3.1) \approx -3.4

b)

The values are too small since g'' is positive for both values of x in. I'm speaking of the x values, 2.9 and 3.1.

Step-by-step explanation:

a)

The point-slope of a line is:

y-y_1=m(x-x_1)

where m is the slope and (x_1,y_1) is a point on that line.

We want to find the equation of the tangent line of the curve g at the point (3,-5) on g.

So we know (x_1,y_1)=(3,-5).

To find m, we must calculate the derivative of g at x=3:

m=g'(3)=(3)^2+7=9+7=16.

So the equation of the tangent line to curve g at (3,-5) is:

y-(-5)=16(x-3).

I'm going to solve this for y.

y-(-5)=16(x-3)

y+5=16(x-3)

Subtract 5 on both sides:

y=16(x-3)-5

What this means is for values x near x=3 is that:

g(x) \approx 16(x-3)-5.

Let's evaluate this approximation function for g(2.9).

g(2.9) \approx 16(2.9-3)-5

g(2.9) \approx 16(-.1)-5

g(2.9) \approx -1.6-5

g(2.9) \approx -6.6

Let's evaluate this approximation function for g(3.1).

g(3.1) \approx 16(3.1-3)-5

g(3.1) \approx 16(.1)-5

g(3.1) \approx 1.6-5

g(3.1) \approx -3.4

b) To determine if these are over approximations or under approximations I will require the second derivative.

If g'' is positive, then it leads to underestimation (since the curve is concave up at that number).

If g'' is negative, then it leads to overestimation (since the curve is concave down at that number).

g'(x)=x^2+7

g''(x)=2x+0

g''(x)=2x

2x is positive for x>0.

2x is negative for x.

That is, g''(2.9)>0 \text{ and } g''(3.1)>0.

So 2x is positive for both values of x which means that the values we found in part (a) are underestimations.

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