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Ira Lisetskai [31]
3 years ago
6

Each statement describes a transformation of the graph of y = x2. Which statement correctly describes the graph of y = (x + 4)2

- 7?
A.
It is the graph of y = x2 translated 4 units down and 7 units to the left.

B.
It is the graph of y = x2 translated 4 units up and 7 units to the left.

C.
It is the graph of y = x2 translated 7 units down and 4 units to the left.

D.
It is the graph of y = x2 translated 7 units down and 4 units to the right.

Mathematics
2 answers:
alina1380 [7]3 years ago
6 0
  • Vertex Form: y=(x-h)^2+k , with (h,k) as the vertex.

So the new equation is in vertex form. And looking at this equation, we see the vertex as (-4,-7) <em>(Remember that y = (x + 4)^2 - 7 can be also written as y = (x - (-4))^2 - 7).</em>

Since negative x-coordinates go to the left on the x-axis and negative y-coordinates go down on the y-axis, <u>your answer is going to be C. It is the graph of y = x^2 translated 7 units down and 4 units to the left.</u>

nataly862011 [7]3 years ago
5 0

It is the graph of y = x² translated 7 units down and 4 units to the left.

<h3>Further explanation</h3>

There are four types of transformation geometry:

  • translation (or shifting),
  • reflection,
  • rotation, and
  • dilation (stretching or shrinking).  

In this case, the transformation is shifting vertically and horizontally.

  • Translation (or shifting): moving a graph on an analytic plane without changing its shape.  
  • Vertical shift: moving a graph upwards or downwards without changing its shape.  
  • Horizontal shift: moving a graph to the left or right downwards without changing its shape.  

Vertical Shift

Given the graph of y = f(x) and v > 0, we obtain the graph of:  

  • \boxed{ \ y = f(x) + v \ } by shifting the graph of \boxed{ \ y = f(x) \ } upward v units.
  • \boxed{ \ y = f(x) - v \ } by shifting the graph of \boxed{ \ y = f(x) \ } downward v units.  

Horizontal Shift

Given the graph of y = f(x) and h > 0, we obtain the graph of:  

  • \boxed{ \ y = f(x + h) \ } by shifting the graph of \boxed{ \ y = f(x) \ } to the left h units.  
  • \boxed{ \ y = f(x - h) \ } by shifting the graph of \boxed{ \ y = f(x) \ } to the right h units.

- - - - - - - - - -

<u>Given:</u>

\boxed{ \ y = x^2 \rightarrow \ ? \rightarrow  \ y = (x + 4)^2 - 7 \ }

Clearly, to obtain the graph of \boxed{ \ y = (x + 4)^2 - 7 \ } we must translate the graph of \boxed{ \ y = x^2 \ }.

  • \boxed{ \ y = x^2 \ } translated 7 units down.
  • It becomes \boxed{ \ y = x^2 - 7 \ }
  • Furthermore, \boxed{ \ y = x^2 - 7 \ } translated 4 units to the left.

Thus, the result is \boxed{ \ y = (x + 4)^2 - 7 \ }

<u>Conclusion</u>

The statement correctly describes the graph of y = (x + 4)² - 7 is the graph of y = x² translated 7 units down and 4 units to the left.

The answer is C.

<h3>Learn more  </h3>
  1. Transformations that change the graph of f(x) to the graph of g(x) brainly.com/question/2415963
  2. The similar problem brainly.com/question/1369568
  3. Which equation represents the new graph brainly.com/question/2527724

Keywords: each statement, describes, a transformation, the graph, y = x², which, correctly, y = (x + 4)² - 7, translation, shifting, left, down, upward, units, up,  horizontal, vertical

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The questions asked are

If you randomly select 4 peanuts

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2. Compute the probability that two or three of the four M&M’s are brown.

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Step-by-step explanation:

Given the following information

Brown=12%. P(B)=0.12

Yellow=15%. P(Y)=0.15

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Question 1.

They are independent events

If there are exactly three brown and the last is not brown

P(B n B n B n B')

P(B)×P(B)×P(B)×P(B')

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2. If two or three are brown

I.e we are going to two brown and two none brown or three brown and one not brown. (P(B)×P(B)×P(B')×P(B'))+ (P(B)×P(B)×P(B'))

(0.12×0.12×0.88×0.88)+(0.12×0.12×0.12×0.88)

0.0112+0.00152

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3. At most three brown out of four then we are going to have

BBBB', BBB'B', BB'B'B', B'B'B'B'

These are the cases of at most three brown.

P(B)×P(B)×P(B)×P(B') + P(B)×P(B)×P(B')×P(B') + P(B)×P(B')×P(B')×PB')+ P(B')×P(B')×P(B')×P(B')=

0.12×0.12×0.12×0.88+ 0.12×0.12×0.88×0.88+ 0.12×0.88×0.88×0.88+ 0.88×0.88×0.88×0.88=0.694

0.694

69.4%

4. At least 3 brown out of four selection

I.e BBBB', BBBB

These are the two options

P(B)×P(B)×P(B)×P(B') + P(B)×P(B)×P(B)×P(B)=

0.12×0.12×0.12×0.88 + 0.12×0.12×0.12×0.12

0.001728

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