Use Pythagorean theorem.
[tex]|ON|^2+|MN|^2=|OM|^2\\\\x^2+x^2=8^2\\\\2x^2=64\ \ \ \ |divide\ both\ sides\ by\ 2\\\\x^2=32\to x=\sqrt{32}\\\\x=\sqrt{16\cdot2}\\\\x=\sqrt{16}\cdot\sqrt2\\\\\boxed{x=4\sqrt2}
Answer: |MN| = 4√2.
Answer:
<h2>x = 24</h2>
Step-by-step explanation:
Multiply through by the LCM that's 6 in order to eliminate the fraction
That's
Using the addition property add 2x to both sides of the equation
That's
<u>Divide both sides by 5</u>
We have the final answer as
<h3>x = 24</h3>
Hope this helps you
Answer:
Step-by-step explanation:
Answer:
[2, 1]
Step-by-step explanation:
By the Elimination method, you are left with 8x = 16 because -8 and 8 are what are called Additive Inverses, meaning they result in 0⃣; x = 2, plug 2⃣ back into both equations, and you will see that y = 1, making the solution above.
Answer:
n=6
Step-by-step explanation:
