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3 years ago

Truck drivers probably cannot see your vehicle if you cannot

2 answers:

7 0

D is the answer to this question. It is very important for people to stay in the right positon before they hit the road.

sergeinik [125]3 years ago

7 0

Answer:

The crrect answer is option B- see the truck driver in his or her side mirrors.

Explanation:

Despite being a larger vehicle, the truck has blind spots, where the driver will lose sight of you.

You will be in this blind spot If you cannot see the truck driver's reflection in his or her side mirror, which will be very dangerous because it could cause an accident, since the driver is not seeing you.

This area where the truck driver cannot see you is called No Zone.

Given this information we can say that the correct answer is option B.

You might be interested in

(Java)Write a program that calculates and displays the conversion of an entered number of dollars into currency denominations—20

Nataly [62]

Answer:

Below!

Explanation:

This is the code I have. I am not sure what I am missing that it won't accept -

import java.util.Scanner;

class Dollars {

public static void main(String[] args) {

int numTwenties,numTens,numFives,numOnes,dollarAmount;

Scanner sc= new Scanner(System.in);

System.out.println("Please enter a dollar amount: ");

dollarAmount = sc.nextInt();

numTwenties = dollarAmount/20;

numTens = (dollarAmount - 20*numTwenties)/10;

numFives = (dollarAmount - (10*numTens + 20*numTwenties))/5;

numOnes = (dollarAmount - (10*numTens + 20*numTwenties + 5*numFives));

System.out.println(+ dollarAmount + " converted is" + numTwenties + " $20s, " + numTens + " $10s, " + numFives + " $5s, and " + numOnes + " $1s.");

}

This is what it is giving me -

Test CaseIncomplete

Dollars 598

Input598

OutputPlease enter a dollar amount: 598

598 converted is29 $20s, 1 $10s, 1 $5s, and 3 $1s.

Results

$598 converted is 29 $20s, 1 $10s, 1 $5s, and 3 $1s

Expected Output

$598 converted is 29 $20s, 1 $10s, 1 $5s, and 3 $1s

8 0

3 years ago

1) List at least five smaller behaviors you could break the complex behavior "brushing my teeth" into.

zhuklara [117]

Q1:
1. Go into the bathroom
2. Put toothpaste on the toothbrush
3. Place head of toothbrush on your teeth
4. Revolve in small circles
5. Repeat 4 for all of your teeth
6. Use water to wash away the toothpaste in you mouth

5 0

3 years ago

Read 2 more answers

If you enter 234.567 into a cell that is formatted to display 1 decimal place, what is the value stored in the cell?

Jobisdone [24]

Answer C because you would round up to .6 since that is the tenths (aka the first) decimal place

4 0

3 years ago

a. Do you think the U.S. government should censor information on the Web, such as instructions for making weapons, to protect th

MrRissso [65]

Answer:

The answer is YES.

Explanation:

Things pertaining to weapons, destructive materials should be shared with precautions or much better if these things should not be put online. Since internet is widely available to almost all types of users and almost to all places, we cannot be sure of who will get hold of these information. Kids could easily see this and gain knowledge and out of curiosity will try these dangerous things. Terrorist groups will also have access to these information and who knows might happen to poor innocent souls around.

I don't think it would violate the right of First Amendment regarding freedom of speech. Freedom should be granted on matters that are most sensible. And this time, we are just protecting the rights of children and other innocent people who can be a victim including you. We are talking about weapons and destructive materials here which is non beneficial if one could get hold of this information, in my opinion. If there is really a need to construct these things, it is better to consult an expert or an authority to ensure that nobody gets harm.

5 0

3 years ago

Write an abstract data type for a queue in Java whose elements are generic elements of type T that have an associated integer pr

Nimfa-mama [501]

Answer:

See explaination

Explanation:

#include<iostream>

const int MAX=20;

class dque

{

private:

int arr[MAX];

int front,rear;

public:

dque();

void addqatbeg(char item);

void addqatend(char item);

int delqatbeg();

int delqatend();

void display();

int count();

};

dque::dque()

{

front=rear=-1;

for(int i=0;i<MAX;i++)

arr[i]=0;

}

void dque::addqatbeg(int item)

{

if(front==0&&rear==MAX-1){cout<<"\nDeque is full"<<endl;return;}

if(front==-1){front=rear=0;arr[front]=item;return;}

if(rear!=MAX-1)

{int c=count();int k=rear+1;

for(int i=1;i<=c;i++){arr[k]==arr[k-1];k--;}

arr[k]=item;front=k;rear++;

}

else{front--;arr[front]=item;}

}

void dque::addqatend(int item)

{

if(front==0&&rear==MAX-1){cout<<"\nDeque is full"<<endl;return;}

if(front==-1){front=rear=0;arr[rear]=item;return;}

if(rear==MAX-1){

int k=front-1;

for(int i=front-1;i<rear;i++){k=i;

if(k==MAX-1)arr[k]=0;

else arr[k]=arr[i+1];

}rear++;

arr[rear]=item;

}

int dque::delqatbeg()

{

if(front==-1){cout<<"\nDeque is empty"<<endl;return0;}

int item=arr[front];

arr[front]=0;

if(front==rear)front=rear=-1;

else

front++;

return item;

}

int dque::delqatend()

{

if(front==-1){cout<<"\nDeque is empty"<<endl;return 0;}

int item=arr[rear];

arr[rear]=0;

rear--;

if(rear==-1)front=-1;return item;

}

void dque::display()

{

cout<<endl<<"front->";

for(int i=0;i<MAX;i++)cout<<""<<arr[i];cout<<"<-rear";

}

int dque::count()

{

int c=0;

for (int i=0;i<MAX;i++){if(arr[i]!=0)c++;}

return c;}

}

7 0

3 years ago

Read 2 more answers