Explanation:
The second for loop does 1 of 4 iterations for every 1 of 5 iterations of the parent loop. meaning it is 4 x 5 which is 20.
Answer:
Explanation:
There are many weaknesses/vulnerabilities, some of which are the following...
Default Network Hardware, many individuals will go out and buy a new router and install it in their home. These devices come with a preset configuration including a preset security password which is many times a default password used for every router of the same model. This can be easily obtained by anyone who can then access the network.
Access Point hacking, an experienced individual can use a packet sniffer to detect the SSID that is frequently sent from the router in order to create an access point to be able to access the network.
WEP encryption is another vulnerability. These are very low security passwords that can be cracked using different software in a short period of time.
These are some of many vulnerabilities that wireless local networks have, but there are also many precautions and security measures that can be taken to prevent them.
It depends on a language you code. I think this could be either C++ or Java. I know answer for both of them.
For C++: <span>address.find("Avenue")
For Java: </span><span>address.indexOf("Avenue")</span>
import turtle
window = turtle.Screen()
tr = turtle.Turtle()
tr.forward(100)
tr.left(90)
tr.forward(100)
tr.left(90)
tr.forward(100)
tr.left(90)
tr.forward(100)
tr.back(100)
tr.left(120)
tr.forward(75)
tr.right(78)
tr.forward(60)
window.mainloop()
In my code, we use the turtle module for the graphics to draw the house with a roof.
Answer:
import java.util.*;
public class MyClass {
public static void main(String args[]) {
Scanner input = new Scanner(System.in);
System.out.print("Input a word: ");
String userinput = input.nextLine();
for(int i =0;i<userinput.length();i+=2) {
System.out.print(userinput.charAt(i));
}
}
}
Explanation:
This line prompts user for input
System.out.print("Input a word: ");
This declares a string variable named userinput and also gets input from the user
String userinput = input.nextLine();
The following iterates through every other character of userinput from the first using iteration variable i and i is incremented by 2
for(int i =0;i<userinput.length();i+=2) {
This prints characters at i-th position
System.out.print(userinput.charAt(i));
