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Umnica [9.8K]
3 years ago
8

5g + 4(-5+3g) = 1 - g

Mathematics
2 answers:
Korvikt [17]3 years ago
8 0
5g + 4(-5 + 3g) = 1 - g 
5g - 20 + 12g = 1 - g 
 17g - 20 = 1 - g 
   \frac{18g}{18} =   \frac{21}{18}
    there can be to answer 
      g = \frac{21}{18} or 
      you can simplify \frac{21/3}{18/3} =  \frac{7}{6} or 1 \frac{1}{6}
 
 
astra-53 [7]3 years ago
5 0
5g+4(-5+3g)=1-g\ \ \ |use\ distributive\ property\ a(b+c)=ab+ac\\\\5g+4(-5)+4(3g)=1-g\\\\5g-20+12g=1-g\\\\5g+12g-20=1-g\\\\17g-20=1-g\ \ \ |add\ 20\ to\ both\ sides\\\\17g=21-g\ \ \ |add\ "g"\ to\ both\ sides\\\\18g=21\ \ \ \ |divide\ both\ sides\ by\ 18\\\\g=\dfrac{21}{18}\\\\g=\dfrac{21:3}{18:3}\\\\\huge\boxed{g=\frac{7}{6}=\frac{6+1}{6}=\frac{6}{6}+\frac{1}{6}=1\frac{1}{6}}
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A local gym instructor has a course load that allows her to teach eight classes. At an interest meeting, 8 people wanted high-­‐
cricket20 [7]

Answer:

<u>The final curse load of the local gym instructor is this:</u>

<u>High-­‐impact aerobics = 1</u>

<u>Low-­‐impact aerobics =  4</u>

<u>Jazzercise = 1</u>

<u>Step exercise = 2</u>

Step-by-step explanation:

1. Let's apportion the class load using the Hamilton method

Number of classes the local gym instructor can teach = 8

Total number of students that want to take a class = 114 (8 people wanted high-­‐impact aerobics, 64 wanted low-­‐impact aerobics, 11 wanted jazzercise, and 31 wanted step exercise)

Standard divisor = 114/8 = 14.25

Now, we can apportion the students in in Standard quotas, this way:

High-­‐impact aerobics = 8/14.25 = 0.5614

Low-­‐impact aerobics = 64/14.25 = 4.49

Jazzercise = 11/14.25 = 0.7719

Step exercise = 31/14.25 = 2.1754

Now, we find the Minimum quota, just considering the whole number and don't taking into account the decimals, this way:

High-­‐impact aerobics = 0

Low-­‐impact aerobics =  4

Jazzercise = 0

Step exercise = 2

As we can see we have 6 classes and there are 2 still pending. Those 2 goes to the classes with the highest decimal portion, in this case, Jazzercise .7719 and High-­‐impact aerobics with .5614.

<u>The final course load is this:</u>

<u>High-­‐impact aerobics = 1</u>

<u>Low-­‐impact aerobics =  4</u>

<u>Jazzercise = 1</u>

<u>Step exercise = 2</u>

7 0
3 years ago
The simplest form of the expression -2x2(x – 5) + x(2x2 – 10x) + x is
Bad White [126]
For this case you must simplify the expression respecting the rules of multiplication of mathematics.
 The steps to simplify the expression are the following:
 First multiply what is in the parentheses
  -2x ^ 2 (x - 5) + x (2x ^ 2 - 10x) + x
  -2x ^ 3 + 10x ^ 2 + 2x ^ 3 - 10x ^ 2 + x
 Then add the terms that have the same exponent
 (-2x ^ 3 + 2x ^ 3) + (10x ^ 2 - 10x ^ 2) + x
  x
 The final simplification is
 x
 answer
 x
4 0
3 years ago
Read 2 more answers
Simplify 4 3 square root 64
Ierofanga [76]

Answer:

\large\boxed{4\sqrt[3]{64}=16}

Step-by-step explanation:

\sqrt[3]{a}=b\iff b^3=a\\\\4\sqrt[3]{64}=(4)(4)=16\\\\\sqrt[3]{64}=4\ \text{because}\ 4^3=64

8 0
3 years ago
What weight of dry substance is in 150g of a 3% substance solution? What weight of an 8% solution can we have with the same weig
Pavlova-9 [17]
The answers are: 4.5 g and 56.25 g respectively.

Since the first type of measurement in this question is weight or mass, I'll suppose that the percentage concentration is % mass/mass. For that type of concentration measurement, just multiply the percentage by the total mass to get the mass of the wanted material.
So 150 g * 3% = 150 g * 0.03 = 4.5g

For the 8% solution with the same amount of dry substance, use the ratio of percentages, multiplied by the mass of the first solution to get the wanted amount of new solution:
3/8 * 150 g = 56.35 g
5 0
3 years ago
PLEASE CAN SOMEONE HELP????
schepotkina [342]

Answer:

figure it out dummy

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
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