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3 years ago

What is the first step that you should undertake when performing a visual analysis of a work of art?

2 answers:

5 0

The first step in performing a visual analysis of a work of art is to analyze whether the artist successfully portrayed the central message in the artwork. It is necessary to know whether or not the central message can be understood by the audience because it implies that the art was able to deliver the essence of what it wishes to deliver. It then becomes easy to understand the other elements in the art.

Anni [7]3 years ago

4 0

Answer:

3.Make a list of the different principles of design used by the artist in the artwork.

Explanation:

It says this in the PLATO tutorial prior to the quiz.

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Wi-Fi Protected Access (WPA) fixes critical vulnerabilities in the earlier wired equivalent privacy (WEP) standard. Understandin

Mars2501 [29]

Since Wi-Fi Protected Access (WPA) fixes critical vulnerabilities in the earlier wired equivalent privacy (WEP) standard, the attacks that is related to encrypted wireless packets is option A: IV attacks.

<h3>Describe an IV attack.</h3>

A wireless network attack is called an initialization vector (IV) attack. During transmission, it alters the IV of an encrypted wireless packet. One packet's plaintext can be utilized by an attacker to calculate the RC4 key stream produced by the IV employed.

Note that A binary vector used to initialize the encryption process for a plaintext block sequence in order to boost security by adding more cryptographic variance and to synchronize cryptographic hardware. The initialization vector is not required to be kept secret.

Learn more about Wi-Fi Protected Access from

brainly.com/question/13068630
#SPJ1

See full question below

Wi-Fi Protected Access (WPA) fixes critical vulnerabilities in the earlier wired equivalent privacy (WEP) standard. Understanding that WPA uses a combination of an RC4 stream cipher and Temporal Key Integrity Protocol (TKIP), this makes a wireless access point NOT vulnerable to which of the following attacks when related to encrypted wireless packets?

IV attacks

Malware

Ransoware

5 0

1 year ago

If userA wants to send a secure message to userB using an asymmetric cryptographic algorithm, which key does userB use to decryp

ANTONII [103]

Answer:

userB will use his/her private key.

Explanation:

The steps involved in using asymmetric cryptographic algorithm are as follow:

1. Each user generates a pair of keys to be used for the encryption and decryption of messages.

2. Each user places one of the two keys in a public register or other accessible file. This is the public key. The companion key is kept private.

3. If UserA wishes to send a confidential message to UserB, UserA encrypts the message using UserB's public key.

4. When UserB receives the message, she decrypts it using her private key.

4 0

3 years ago

What is a disadvantage of shopping online?A.Harder to compare prices than in storesB.A higher risk of financial data theftC.More

babymother [125]

.A higher risk of financial data theftC

7 0

3 years ago

Read 2 more answers

In c please

Paraphin [41]

Answer:

#include <stdio.h>

#include <ctype.h>

void printHistogram(int counters[]) {

int largest = 0;

int row,i;

for (i = 0; i < 26; i++) {

if (counters[i] > largest) {

largest = counters[i];

}

for (row = largest; row > 0; row--) {

for (i = 0; i < 26; i++) {

if (counters[i] >= row) {

putchar(254);

}

else {

putchar(32);

}

putchar(32);

}

putchar('\n');

}

for (i = 0; i < 26; i++) {

putchar('a' + i);

putchar(32);

}

int main() {

int counters[26] = { 0 };

int i;

char c;

FILE* f;

fopen_s(&f, "story.txt", "r");

while (!feof(f)) {

c = tolower(fgetc(f));

if (c >= 'a' && c <= 'z') {

counters[c-'a']++;

}

for (i = 0; i < 26; i++) {

printf("%c was used %d times.\n", 'a'+i, counters[i]);

}

printf("\nHere is a histogram:\n");

printHistogram(counters);

}

5 0

3 years ago

Suppose that the format for license plates in a certain state is two letters followed by four numbers. (a) How many different pl

Ymorist [56]

Answer:

(a) 6,760,000 plates

(b) 3,407,040 plates

Explanation:

The very first thing to note about this question is the number of characters involved in the license plate format (6 characters in this case; 2 letters and 4 numbers). The letters come first and then the numbers follow.

There are a total of 26 possible letters (A-Z) and 10 possible numbers (0 - 9) that can be chosen. We can then proceed to the first question;

(a) Here, the total number of possible plates is to be determined. This is done as follows:

Character 1 (Letter): There are 26 possible letters

Character 2 (Letter): There are 26 possible letters

Character 3 (number): There are 10 possible numbers

Character 4 (number): There are 10 possible numbers

Character 5 (number): There are 10 possible numbers

Character 6 (number): There are 10 possible numbers

So, total number of different plates will be obtained by multiplying all the possibilities: 26 × 26 × 10 × 10 × 10 × 10 = 6,760,000 plates

(b) This second part puts a constraint on the usage of the numbers, unlike the question (a), where there was no constraint at all.

Since there is no constraint on the letters, we can write that:

Character 1 (Letter): There are 26 possible letters

Character 2 (Letter): There are 26 possible letters

For the first number as well, we can write:

Character 3 (number): There are 10 possible numbers

However, for the remaining characters, the possibilities will continually reduce by a value of 1, since we can not use a number that has been used before. So,

Character 4 (number): There are 9 possible numbers

Character 5 (number): There are 8 possible numbers

Character 6 (number): There are 7 possible numbers

So, total number of different plates will be: 26 × 26 × 10 × 9 × 8 × 7 = 3,407,040 plates

(c) Here, repetitions are allowed as in questions (a), but there can not be four zeros. This implies that the maximum number of zeros in any plate will be three. Thus, there will be maximum possibilities on all characters until the last one which will be constrained.

Character 1 (Letter): There are 26 possible letters

Character 2 (Letter): There are 26 possible letters

Character 3 (number): There are 10 possible numbers

Character 4 (number): There are 10 possible numbers

Character 5 (number): There are 10 possible numbers

Character 6 (number): There are 9 possible numbers

Total number of plates will therefore be: 26 × 26 × 10 × 10 × 10 × 9 = 6,084,000 plates.

7 0

3 years ago