NumPy is the key scientific Python computing package. This makes things simpler to display large numbers of data in advanced maths and other operating types. These operations are typically extra efficient and less code-based than that of the built-in sequences in Python are possible, and the further discussion can be defined as follows:
- It offers a multidimensional array object, as do variations such as masks and matrixes that can be used for different mathematical activities.
- It is an external library of basic levels in Python used for complex mathematical procedures.
- It has integrated functions that <em><u>convert various algorithms into arrays</u></em>.
So, the answer is "NumPy".
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brainly.com/question/24817911
Is this for a test, because someone else asked that.
Answer:
actual_value = float(input("Enter the actual value of a piece of property: "))
tax_rate = float(input("Enter the current tax rate for each $100.00 of assessed value: "))
assessed_value = actual_value * 0.6
tax = (assessed_value * tax_rate) / 100
print("The annual property tax is $" + str(tax))
Explanation:
*The code is in Python.
Ask the user to enter the actual value and the tax rate
Calculate the assessed value, multiply the actual value by 0.6
Calculate the tax, multiply the assessed value by the tax rate and divide result by 100
Print the tax
One technical issue I had was on Windows 8.1, with the charm menu not working. The troubleshooting steps to fix it was I did CTRL+SHIFT+ESC to open task manager. I then found Windows Explorer and clicked "Reload." Then everything was fine.
Hope This Helped!
Answer:
To check if the year comes under each 100th year, lets check if the remainder when dividing with 100 is 0 or not.
Similarly check for 400th year and multiple 0f 4. The following C program describes the function.
#include<stdio.h>
#include<stdbool.h>
bool is_leap_year(int year);
void main()
{
int y;
bool b;
printf("Enter the year in yyyy format: e.g. 1999 \n");
scanf("%d", &y); // taking the input year in yyyy format.
b= is_leap_year(y); //calling the function and returning the output to b
if(b==true)
{
printf("Thae given year is a leap year \n");
}
else
{
printf("The given year is not a leap year \n");
}
}
bool is_leap_year(int year)
{
if(year%100==0) //every 100th year
{
if(year%400==0) //every 400th year
{
return true;
}
else
{
return false;
}
}
if(year%4==0) //is a multiple of 4
{
return true;
}
else
{
return false;
}
}
Explanation:
Output is given as image
