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3 years ago

5

What is 0.800 rounded to nearest tenth

1 answer:

arsen [322]3 years ago

5 0

0.800 rounded to the nearest tenth is0.8

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Solve the equation for all real values of x.<br> cosxtanx - 2 cos x=-1

IceJOKER [234]

Solution to equation $cosxtanx - 2 cos^2 x=-1$ for all real values of x is $x=2k\pi + \frac{\pi}{6} , x=2k\pi + \frac{5\pi}{6}$ .

<u>Step-by-step explanation:</u>

Here we have , $cosxtanx - 2 cos^2 x=-1$ . Let's solve :

⇒ $cosxtanx - 2 cos^2 x=-1$

⇒ $cosx(\frac{sinx}{cosx}) - 2 cos^2 x=-1$

⇒ $sinx = 2 cos^2 x-1$

⇒ $sinx = 2 (1-sin^2x)-1$

⇒ $sinx = 1-2sin^2x$

⇒ $2sin^2x+sinx-1=0$

By quadratic formula :

⇒ $sinx = \frac{-b \pm \sqrt{b^2-4ac} }{2a}$

⇒ $sinx = \frac{-1 \pm \sqrt{1^2-4(2)(-1)} }{2(2)}$

⇒ $sinx = \frac{-1 \pm3}{4}$

⇒ $sinx = \frac{1}{2} , sinx =-1$

⇒ $sinx = sin\frac{\pi}{6} , sinx = sin\frac{3\pi}{2}$

⇒ $x=\frac{\pi}{6} , x=\frac{3\pi}{2}$

But at $x=\frac{3\pi}{2}$ we have equation undefined as $cos\frac{3\pi}{2}=0$ . Hence only solution is :

⇒ $x=\frac{\pi}{6}$

Since , $sin(\pi -x)=sinx$

⇒ $x=\pi -\frac{\pi}{6} = \frac{5\pi}{6}$

Now , General Solution is given by :

⇒ $x=2k\pi + \frac{\pi}{6} , x=2k\pi + \frac{5\pi}{6}$

Therefore , Solution to equation $cosxtanx - 2 cos^2 x=-1$ for all real values of x is $x=2k\pi + \frac{\pi}{6} , x=2k\pi + \frac{5\pi}{6}$ .

3 0

3 years ago

What is the product of (3x - 2)(2x^2 + 5)?

MrMuchimi

Answer:

6x^(3)-4x^(2)+15x-10

Step-by-step explanation:

3 0

4 years ago

Solve for x<br> C. 120<br> 2x<br> 3x<br> D. (2x+6)<br> X<br> 126

brilliants [131]

Answer:

x=32

Step-by-step explanation:

i took the test

4 0

3 years ago

Which of the following represents graph of f(x) = (1/2)^x

Alona [7]

heyy, I know you posted this on 2017 and got no answers yet, well i need it this answer and it wasn't here, so i know the answer

The answer is The first one

Thank u :)

6 0

3 years ago

Read 2 more answers

Help plz I don't understand

Vedmedyk [2.9K]

You would multiply 36 and 6 to get x

5 0

4 years ago