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Grace [21]
3 years ago
6

I WILL REWARD BRAINLIEST

Mathematics
2 answers:
Alex Ar [27]3 years ago
8 0
It doesnt equal either of them 10 only = 10
svet-max [94.6K]3 years ago
3 0
3,628,800
Ultimately you do this: 10*9*8*7*6*5*4*3*2*1
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A rectangle’s length is 5 inches more than twice its width. Its area is 50 square inches. Which equation can be used to find its
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Answer:

w(2w+5) = 50

Step-by-step explanation:

length x width = 50

length = 2w+5

4 0
2 years ago
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Please help me?!<br> I need help!?
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Answer:

Area = 6.25\pi ft^2

Step-by-step explanation:

Area = \pi \\r^{2}

The diameter is 5 feet.  That makes the radius 2.5 feet

Area = \pi \\r^{2}

Area = \pi \\2.5^{2}

Area = 6.25\pi ft^2

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Which is the simplified form of the expression ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript nega
AlekseyPX

Answer:

The option "StartFraction 1 Over 3 Superscript 8" is correct

That is \frac{1}{3^8} is correct answer

Therefore [(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}

Step-by-step explanation:

Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2

To find the simplified form of the given expression :

[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2

=(2^{-2})^{-3}(3^4)^{-3}\times (2^{-3})^2(3^2)^2 ( using the property (ab)^m=a^m.b^m )

=(2^6)(3^{-12})\times (2^{-6})(3^4) ( using the property (a^m)^n=a^{mn}

=(2^6)(2^{-6})(3^{-12})(3^4) ( combining the like powers )

=2^{6-6}3^{-12+4} ( using the property a^m.a^n=a^{m+n} )

=2^03^{-8}

=\frac{1}{3^8} ( using the property a^{-m}=\frac{1}{a^m} )

Therefore [(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}

Therefore option "StartFraction 1 Over 3 Superscript 8" is correct

That is \frac{1}{3^8} is correct answer

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3 years ago
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