For no real solution, you must have b^2 - 4ac of the quadratic formula be less than 0.
a = 1; b = 2; c = C
b^2 - 4ac < 0
2^2 - 4(1)(C) < 0
4 - 4C < 0
-4C < -4
C > 1
The only choice greater than 1 is 3.
Answer: the 4th choice, 3
So he goes from side 2 to side 4 there is his cut have a nice day sir/maam
Answer:
y= 2.6
Step-by-step explanation:
Short answer: C
Remark
Since b is all by itself in equation 2, Substitute it into equation 1.
2a + 3b = 5
b = a - 5 Put this result in equation 1. Be sure and use brackets.
2a + 3(a - 5) = 5 Remove the brackets.
2a + 3a - 15 = 5 Notice the -5 inside the brackets becomes - 15
Combine like terms on the left.
5a - 15 = 5 Add 15 to both sides
5a = 5 + 15
5a = 20 Divide by 5
a = 20/5
a = 4
So far, c is the only possible answer.
b = a - 5
b = 4 - 5
b = - 1