Answer:
x = 17 ft ... ( nearest 10th of a foot )
Step-by-step explanation:
Given:-
- The side length of inner square = x ft
- The side length of outer square = 20 ft
Find:-
Find the side length of the inner square that would make the area of the inner square equal to 75% of the total area of the garden.
Solution:-
- Compute the area of the inner square (A_i) using side length (x):
A_i = side length ^2
A_i = x^2 ft^2
- The area of the entire garden is the area (A_o) of the outer square with side length equal to 20 ft.
A_o = side length ^2
A_o = 20^2
A_o = 400 ft^2
- The 75% of the entire garden is :
(75 / 100)*A_o
(75 / 100)*400
300 ft^2
- The area of the inner square is 75% of the entire garden the mathematical expression for it is:
A_i = 300 ft^2
x^2 = 300 ft^2
- The side length required for the inner square is the solution to the quadratic equation above:
x = √300
x = 17.320508ft.
x = 17 ft ... ( nearest 10th of a foot )
Answer:
3x^2 + 12x + 4y^2 - 8y = 32
Step-by-step explanation:
3(x^2+4x)+4(y^2-2y)=32
At first we have to break the parenthesis to get the variables in normal position. To break those, we have to multiply each with the help of algebraic expression:
or, (3*x^2) + (3 × 4x) + (4 × y^2) - (4 × 2y) = 32
or, 3x^2 + 12x + 4y^2 - 8y = 32
Since the equation does not have anything to add or deduct, therefore, it is the answer.
Answer:
12.3
Step-by-step explanation:
A^2 + B^2 = C^2
11^2 + 4.5^2 = C^2
132 + 20.25 = C^2
152.25 = C^2
Square root of 152.25 = 12.3
STEP - BY - STEP EXPLANATION
What to find?
The the value of secθ.
Given:
(4, 3)
⇒(x, y) = (4, 3)
Step 1
Draw a sketch.
Step 2
Substitute the values into the trig. ratio formula below.
![tan\theta=\frac{opposite}{adjacent}](https://tex.z-dn.net/?f=tan%5Ctheta%3D%5Cfrac%7Bopposite%7D%7Badjacent%7D)
From the sketch above, opposite = 3 and adjacent = 4
![tan\theta=\frac{3}{4}](https://tex.z-dn.net/?f=tan%5Ctheta%3D%5Cfrac%7B3%7D%7B4%7D)
Step 3
Find the value of the hypotenuse side using Pythagoras theorem.
let h be the hypotenuse side.
![\begin{gathered} h^2=4^2+3^2 \\ \\ =16+9 \\ \\ =25 \\ \\ h=5 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20h%5E2%3D4%5E2%2B3%5E2%20%5C%5C%20%20%5C%5C%20%3D16%2B9%20%5C%5C%20%20%5C%5C%20%3D25%20%5C%5C%20%20%5C%5C%20h%3D5%20%5Cend%7Bgathered%7D)
Hence, hypotenuse = 5
Step 4
Substitute the values into the formula below:
![\begin{gathered} cos\theta=\frac{adjacent}{hypotenuse} \\ \\ =\frac{4}{5} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20cos%5Ctheta%3D%5Cfrac%7Badjacent%7D%7Bhypotenuse%7D%20%5C%5C%20%20%5C%5C%20%3D%5Cfrac%7B4%7D%7B5%7D%20%5Cend%7Bgathered%7D)
But,
![sec\theta=\frac{1}{cos\theta}=\frac{1}{\frac{4}{5}}=\frac{5}{4}](https://tex.z-dn.net/?f=sec%5Ctheta%3D%5Cfrac%7B1%7D%7Bcos%5Ctheta%7D%3D%5Cfrac%7B1%7D%7B%5Cfrac%7B4%7D%7B5%7D%7D%3D%5Cfrac%7B5%7D%7B4%7D)
ANSWER
secθ= 5/4
tanθ=3/4