Answer:I think Jordan is this a trick question
Step-by-step explanation:
Wait, this is simplified because there are no common terms.
There are 
ways of picking 2 of the 10 available positions for a 0. 8 positions remain.
There are 
ways of picking 3 of the 8 available positions for a 1. 5 positions remain, but we're filling all of them with 2s, and there's 
way of doing that.
So we have
The last expression has a more compact form in terms of the so-called multinomial coefficient,
The answer is (n+11)(n-4). You want to find what multiplies to make -44 and what adds to make 7.
