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yulyashka [42]
3 years ago
6

What is 12 divided by one third

Mathematics
2 answers:
Charra [1.4K]3 years ago
5 0
12 divided by 1/3 is the same as doing 12x3 so it's 36
inessss [21]3 years ago
3 0
\frac{12}{ \frac{1}{3} }=12÷ 1/3=12*3=36
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Sallie Woo worked these hours last week: Monday, 10; Tuesday, 8 1/4; Wednesday, 9 1/2; Thursday, 6; Friday, 8; Saturday, 5. Sall
almond37 [142]

Answer:

Her pay for the week= $ 611.325

Step-by-step explanation:

Sallie is paid $ 11.40 per hour for regular hours.

The total regular hours worked during the week are

Monday + Tuesday + Wednesday + Thursday+ friday = 8 + 8+ 8+6+8= 38 hours

She works overtime during the week

Monday + Tuesday + Wednesday = 2+ 1/4+  1 1/2=  2+ 1/4 + 3/2

= 8 +1+ 6/4=15/4 = 3 3/4 hours

Over the weekend she works five hours .

So the total pay would be

$ 11.40( 38 ) + $ 11.40( 1.5) (  15/4) + $ 11.40 ( 2) ( 5)

= 433.2 + 64.125 + 114.0

= $ 611.325

3 0
3 years ago
624,612 rounded to the nearest hundred is
Dimas [21]

Answer:

624 600

Step-by-step explanation:

624 <u>6</u>12

you have to concentrate at the 1 because because it's at the tens place, if the 1 is not greater than 5 you don't have to do anything. you just have to remove the two numbers before the the number 6 and you so it automatically should be 624 600.

To round a number to the nearest hundredth , look at the next place value to the right (the tens this time). Same deal: If it's 4 or less, just remove all the digits to the right. If it's 5 or greater, add 1 to the digit in the hundredths place, and then remove all the digits to the right.

3 0
3 years ago
What is the maximum slope to f(x)= e^(-x^2)?
MA_775_DIABLO [31]
F'(x)=-2x{e^(-x²)}
Equating f'(x)=0,
i.e,

-2x{e^(-x²)}=0....eqn(i)
For maximum slope:
Differentiating (i) wrt x,we get,
4x² {e^(-x²)}-2 {e^(-x²)}=0
{e^(-x²)} [4x²-2]=0
4x²-2=0
x=1/√2

If f(x)=y then f'(x)=dy/dx=slope
So,
Maximum slope
= f'(x)
= -2x{e^(-x²)}
=-2×(1/✓2){e^(-1/✓2)²}
= -✓2{e^(-1/2)}
=(-sqrt 2/sqrt e)
=-sqrt(2/e)➡c is correct



6 0
3 years ago
Calculate the number of kilograms of mercury required to fill a pool that is 20.0 m x 50.0 m x 10.0 m. The density of mercury is
malfutka [58]

Answer:

m=135000000 Kg

Step-by-step explanation:

To find the number of kilograms of mercury we need to find how to relate density, mass and, volume. For this we shall recall the density formula:

\rho=\frac{m}{V}

where \rho is the density, m is the mass and, V is the volume.

We have the density and want to compute the mass so now we want to know the volume of the pool.

The volume of a rectangular pool is given by the fomula:

V= (length)(heigh)(width).

So for our pool

V= (20)(50)(10).

V= 10000m^{3}.

Our density is in g/mL, so the last thing we need to do before computing the mass is to express the density in Kg/m^{3} (this is because we want our mass in Kg and, we have our volume in m^{3}).

For the density conversion we have to remember that

1000mL = 1L

1L=0.001m^{3}

1000g=1Kg

so

\rho=13.5\frac{g}{mL}*\frac{1000mL}{1L}*\frac{1L}{0.001m^{3}}*\frac{1Kg}{1000g}   =13500\frac{Kg}{m^{3}}.

With this we can finally compute mass:

\rho=\frac{m}{V}

m=\rho*V

m=(13500*10000) Kg

m=135000000 Kg.

4 0
3 years ago
The difference of 15 and x is 12
gulaghasi [49]

Answer:

X is 3

Step-by-step explanation:

15-x=12

X=15-12

X=3

8 0
3 years ago
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