Answer:
Radius
Step-by-step explanation:
A circle is made of specific components which define its shape. It has a fixed center which is equidistant apart from all points at its edge. The distance from the center to each point is called its radius. The distance from its edge through its center to the opposite edge is called the diameter.
850 x 0.05 = 42.5
850 + 42.5 = 892.5
She earned 42.5
And 892.5 she wardens at the end of four years
A is 6:55
B is 37 Minutes
C is 15:12
Step-by-step explanation:
so basically its just adding minutes to a clock, like if its 1:00 o clock and 40 minutes pass it will be 1:40 or if its 12:00 and 25 minutes pass it will be 12:55. There's 60 minutes in an hour so if the time is, let's say, 12:45 and 30 minutes go by itd be 1:15.
C is a little more tricky but thats just because its military time.:) basically instead of going to 12 am to 1 pm it would go from 12:00 AM to 13:00 PM
Answer:
(d + 3) would be 10
Step-by-step explanation:
<u>Step 1: Distribute</u>



<u>Step 2: Subtract 13.5 from both sides</u>


<u>Step 3: Divide both sides by 4.5</u>


<u>Step 4: Determine what (d+3) is</u>



Answer: (d + 3) would be 10
Hmmm the object, is at rest, when dropped, so it has a velocity of 0 ft/s
the only force acting on the object, is gravity, using feet will then be -32ft/s²,
was wondering myself on -32 or 32.. but anyhow... we'll settle for the negative value, since it seems to be just a bit of convention issues
so, we'll do the integral to get v(t) then

when will it reach the ground level? let's set s(t) = 0

part B) check the picture below