Using the z-distribution, it is found that a sample of 171 should be selected.
<h3>What is a z-distribution confidence interval?</h3>
The confidence interval is:
The margin of error is:
In which:
is the sample mean.
is the standard deviation for the population.
For this problem, the parameters are:
Hence we solve for n to find the needed sample size.
n = 170.7.
Rounding up, a sample of 171 should be selected.
More can be learned about the z-distribution at brainly.com/question/25890103
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Answer:
The second and fourth one is right
Step-by-step explanation:
A²+ B² = C²
15² + 20² = 25²
225 + 400 = 625
625 = 625
16² + 30² = 34²
256 + 900 = 1156
1156 = 1156
They both check out
<span>So we wan't to know what is the sum of 3 2/3 and 14 2/5. First lets turn them into fractions: first one is 11/3 and the second is 72/5. Now lets add them: We multiply fractions this way: (a/b)+(c/d)={(a*d)+(c*b)}/(b*d). Following this rule: {(11*5)+(72*3)}/(3*5)={55+146}/15=201/15. and finally lets turn it back into a mixed number: 13 6/15</span>
Answer:
(x-1) ( x -i) (x+i)
Step-by-step explanation:
x^3 -2x^2 +x-2
Factor by grouping
x^3 -2x^2 +x-2
x^2(x-2) +1(x-2)
Factor out (x-2)
(x-2) (x^2+1)
Rewriting
(x-1) ( x^2 - (-1)^2)
(x-1) ( x -i) (x+i)
Answer: 1.5miles/hour
Step-by-step explanation:
