n=8320987125437793528348710310901843271933297732006335848276356027645952000000000000
So you can see there are 12 zeros before you hit the first non-zero, which is 2.
The first one and the last one
The probability of those sequence of events is 2/21
Answer: (x, y) = ( -2, -3 )
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Work Shown:
2x+y = -7
2( x ) + y = -7
2( 4+2y ) + y = -7 .... plug in x = 4+2y
2*4 + 2*2y + y = -7
8 + 4y + y = -7
5y+8 = -7
5y = -7-8 .... subtract 8 from both sides
5y = -15
y = -15/5 ... divide both sides by 5
y = -3
This y value pairs with...
x = 4 + 2y
x = 4 + 2(-3)
x = 4 - 6
x = -2
So we have (x, y) = (-2, -3) as the solution to the system.
