this can be solve using newtons heating of cooling
(Ts – T) =(Ts – To)*e^(-kt)
Where Ts is the ambient temperature
To is initial temperature
T is the temperature at time t
t is the time
k is constant
fisrt solve the constant k for the given first scenario
(99 – 36) = (99 – 46)*e(-5k)
K = -0.0346
Using k, solve T at t = 13 min
(99 – 46) = (99 – T)*e(-13*(-0.0346)
T = 58.82 degree F
Answer:
a = 1
b = 3
c = 1
d = 2
e = 6
f = 8
Step-by-step explanation:
Any integer with power as zero = 1
<h3>
For a</h3>
2^x
2^0
= 1
<h3>
For b</h3>
3 * 2^x
3 * 2^0
3 * 1
= 3
<h3>
For c</h3>
2 ^ 3(x)
2 ^ 3(0)
2 ^ 0
= 1
<h3>For d</h3>
2^1
= 2
<h3>
For e</h3>
3 * 2^x
3 * 2^1
3 * 2
= 6
<h3>For f</h3>
2 ^ 3(x)
2 ^ 3(1)
2 ^ 3
2 * 2 * 2
= 8
Hey there! I'm happy to help!
Here's how to find the slope given any two points.
Subtract the y values.
14-(-18+-14+18=32
Subtract the x values.
-6-2=-8
And divide those.
32/-8=-4
The slope is -4.
Have a wonderful day! :D
Step-by-step explanation:
1 pound = 453.592 grams for approximate result we can use 454 so
We have to find 22 pounds into grams
= 454 x 22 = 9988 grams
It is possible to calculate mathematically the area under the normal curve between any two values of z.
However, tables/software have been developed to give the areas under the normal curve to the left of particular values of z. The function is the probability of Z<z, or P(Z<z).
The area between two values z1 and z2 (where z2>z1) is therefore
P(Z<z2)-P(Z<z1).
For example, to find the area between z1=1.5, z2=2.5
is
P(Z<2.5)-P(Z<1.5)
=0.99379-0.93319
=0.06060
(above values obtained by software, such as R)
For example, the value P(Z<2.5) can be calculated using
P(Z<2.5)=erf(2.5/sqrt(2))/2+1/2
where erf(x) is a mathematical function that does not have an explicit formula (calculated by summation of series, or tabulated).
