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anygoal [31]
3 years ago
6

A project is found to have expected time T = 35.33 days and variance V = 3.22.

Mathematics
1 answer:
Goryan [66]3 years ago
7 0

Answer:

a) z = \frac{40-35.33}{1.794}= 2.60

b) z = \frac{40-35.33}{1.794}= 2.60

c) z = \frac{30-35.33}{1.794}= -2.97

Step-by-step explanation:

For this case we know that the mean for the random variable of interest is \mu = 35.33 and the variance \sigma^2 = 3.22 so then the deviation would be \sigma = \sqrt{3.22}= 1.794

The z score is given by thsi formula:

z = \frac{X -\mu}{\sigma}

Part a

We want this probability:

P(X>40)

And if we find the z score we got:

z = \frac{40-35.33}{1.794}= 2.60

And we can find this probability: P(Z>2.60)

Part b

We want this probability:

P(X

And if we find the z score we got:

z = \frac{40-35.33}{1.794}= 2.60

And we can find this probability: P(Z

Part c

We want this probability:

P(X

And if we find the z score we got:

z = \frac{30-35.33}{1.794}= -2.97

And we can find this probability: P(Z

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