Ya'll how do I graph this? I haven't graphed anything in 3 years

Mathematics

1 answer:

Artyom0805 [142]2 years ago

4 0

Answer:

I hope you get it .............

You might be interested in

Which step is incorrect? Look at picture

asambeis [7]

Answer: step 4 is incorrect

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

What is (2a-1)(8a-5)

Umnica [9.8K]

Answer:

$16a^{2} - 18a + 5$

Step-by-step explanation:

1) Use the grid method to expand the two brackets

2) Collect like terms

3) Form the statement!

(See attached image)

Download pdf

5 0

2 years ago

Consider the matrix shown below:

velikii [3]

Answer:

$A)\ \ \ \ \left[\begin{array}{ccc}8&-5\\-3&2\\\end{array}\right]$

Step-by-step explanation:

Given the matrix: $\left[\begin{array}{ccc}2&5\\3&8\\\end{array}\right]$ , it's inverse is calculated using the formula:

$\left[\begin{array}{ccc}a&b\\c&d\\\end{array}\right]^{-1}=\frac{1}{det\left[\begin{array}{ccc}a&b\\c&d\\\end{array}\right] }\left[\begin{array}{ccc}d&-b\\-c&a\\\end{array}\right]$

#Therefore, we calculate as;

$\frac{1}{det\left[\begin{array}{ccc}2&5\\3&8\\\end{array}\right] }\left[\begin{array}{ccc}8&-5\\-3&2\\\end{array}\right] \\\\\\\\\#det\left[\begin{array}{ccc}2&5\\3&8\\\end{array}\right] =1\\\\\\\\=\frac{1}{1}\left[\begin{array}{ccc}8&-5\\-3&2\\\end{array}\right] \\\\\\\\=\left[\begin{array}{ccc}8&-5\\-3&2\\\end{array}\right]$