Question

I don’t understand plz I struggle with math so much plz help !

Answer 1

To solve the problem, set up a proportion like this:

$\frac{5}{7} = \frac{20}{x}$

The important thing to note here is that the fractions are proportionate to one another.  Meg's cat is in the numerator while Anne's cat is in the denominator.  Use cross multiplication to solve for the weight of Anne's cat.

$5x = 7 * 20 \\ 5x = 140 \\ x=28$

Anne's cat weighs 28 kgs.  The question asked how much more her cat weighs than Meg's, so use subtraction:

28 - 20 = 8

Anne's cat weighs 8 kgs more than Meg's cat.

Answer 2

If the ratio is 5:7 and Meg's cat is 20 kilograms, we can say that 5*4(to figure this out, divide 20 by 5 in this problem) would be 20. We know what Meg's cat is 20 kilograms, but we need Anne's cat. Do the same thing, except with the other number in the ratio-7. Seven times 4 would equal 28. We are not done yet though. We need to know how many MORE kilograms Anne's cat is than Meg's cat. So, you would do 28 - 20 to equal 8 kilograms. Anne's cat is 8 kilograms more than Meg's cat. I hope this helps!