Answer:
One leap year contains <em><u>8784</u></em> hours. Hope this helps. :)
{tan(60) + tan(10)}/{1 - tan(60)*tan(10)} - {tan(60) - tan(10)}/{1 + tan(10)*tan(60)}
<span>ii) Taking LCM & simplifying with applying tan(60) = √3, the above simplifies to: </span>
<span>= 8*tan(10)/{1 - 3*tan²(10)} </span>
<span>iii) So tan(70) - tan(50) + tan(10) = 8*tan(10)/{1 - 3*tan²(10)} + tan(10) </span>
<span>= [8*tan(10) + tan(10) - 3*tan³(10)]/{1 - 3*tan²(10)} </span>
<span>= [9*tan(10) - 3*tan³(10)]/{1 - 3*tan²(10)} </span>
<span>= 3 [3*tan(10) - tan³(10)]/{1 - 3*tan²(10)} </span>
<span>= 3*tan(30) = 3*(1/√3) = √3 [Proved] </span>
<span>[Since tan(3A) = {3*tan(A) - tan³(A)}/{1 - 3*tan²(A)}, </span>
<span>{3*tan(10) - tan³(10)}/{1 - 3*tan²(10)} = tan(3*10) = tan(30)]</span>
X=11 I say .......... ...
Answer:
B) A < 0
Step-by-step explanation:
I had the same question, and got it right.
Answer:
<em>6,174</em>
Step-by-step explanation:
(-33 * - 78) + (5 * 8 * 9 * 10)
Remove the brackets:
-33 * - 78 + 5 * 8 * 9 * 10
Solve like so:
-33 * - 78 = 2,574
5 * 8 * 9 * 10 = 3,600
(2,574) + (3,600)
2,574 + 3,600 = 6,174
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