A gallon of gasoline cost 30 cents in 1960 an
$1.30 in 1980
percent increase in the price = ?
first we have to convert cents into dollars so that both amounts have to be in same unit
30 cents = $0.3
increase in gasoline cost = $1.30 - 0.3 = $1
now for calculating percent increase divide this with the new amount and than multiply with 100
percent increase = ($1 / $1.30) x 100 = 76.92% = 77% approx.
so, there is 77% increase in the price of gasoline
Answer:
$0.70 or one soda
Step-by-step explanation:
$8.40 / 12 = $0.70
Hope this helps! Mark brainliest please. Have a nice day!
Answer:
x = 6
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
Step-by-step explanation:
<u>Step 1: Define Equation</u>
3 - 2x = -1.5x
<u>Step 2: Solve for </u><em><u>x</u></em>
- Add 2x on both sides: 3 = 0.5x
- Divide 0.5 on both sides: 6 = x
- Rewrite: x = 6
<u>Step 3: Check</u>
<em>Plug in x into the original equation to verify it's a solution.</em>
- Substitute in<em> x</em>: 3 - 2(6) = -1.5(6)
- Multiply: 3 - 12 = -9
- Subtract: -9 = -9
Here we see that -9 does indeed equal -9.
∴ x = 6 is the solution to the equation.
