Answer:
There are no real values of x for point P to belong to the 4 quadrant
Step-by-step explanation:
<u><em>The question in English is</em></u>
To what real values of x does the point P (3x -6, 2x +4) belong to the 4th quadrant?
we know that
A point in the fourth Quadrant has the x-coordinate positive and the y-coordinate negative
we have the point
P (3x-6, 2x+4)
----> inequality A ( x-coordinate must be positive)
---> inequality B ( y-coordinate must be negative)
Solve Inequality A
-----> (2,∞)
Solve Inequality B
----> (-∞,-2)
The solution of the system is
(-∞,-2) ∩ (2,∞)
therefore
The system has no solution
There are no real values of x for point P to belong to the 4 quadrant
X = 8/3
I hope this helped!
These are from least to greatest 1.6,1.64,16,4,16.009
Let's break this down:
The difference: Something's gotta be subtracted
Twice a number: So 2 times a number, or n
and 3: So we gotta subtract 2n and 3
is 11: The final answer is 11
So altogether is:
2n - 3 = 11
can u show me a shorter verison