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4 years ago

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A large container holds 8 gallons of water. It begins leaking at a constant rate. After 48 minutes, the container has 5 gallons

of water left. What rate is the water leaking out at

1 answer:

Mashutka [201]4 years ago

7 0

One gallon per every 16 minute. 8g - 5g = 3g
48 minutes ÷ 3gallons = 16 minute per reduced gallon.

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Brian invests ?1900 into a savings account. The bank gives 3.5% compound interest for the first 2 years and 4.9% thereafter. How

Scorpion4ik [409]

let's check how much is it after 2 years firstly.

$\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &1900\\ r=rate\to 3.5\%\to \frac{3.5}{100}\dotfill &0.035\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases} \\\\\\ A=1900\left(1+\frac{0.035}{1}\right)^{1\cdot 2}\implies A=1900(1.035)^2\implies A=2035.3275$

Brian invested the money for 6 years, so now let's check how much is that for the remaining 4 years.

$\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &2035.3275\\ r=rate\to 4.9\%\to \frac{4.9}{100}\dotfill &0.049\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &4 \end{cases}$

$\bf A=2035.3275\left(1+\frac{0.049}{1}\right)^{1\cdot 4}\implies A=2035.3275(1.049)^4 \\\\\\ A\approx 2464.54\implies \boxed{\stackrel{\textit{rounded up }}{A=2465}}$

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3 years ago

Match each number with its place in order from smallest (1st) to largest (6th).

zheka24 [161]

90 would be the largest then 59,48, -56, -80, and leaving -84 to be the smallest

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3 years ago

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4 years ago

Determine the period.

Aliun [14]

Answer:

T = 3

Step-by-step explanation:

To find the period, find the distance it takes to complete one cycle.

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3 years ago

Please help!<br><br> <img src="https://tex.z-dn.net/?f=%5Cfrac%7B4.2%7D%7B7%5Cfrac%7B5%7D%7B7%7D%20%7D%20%3D%20%20%5Cfrac%7B3%5C

emmasim [6.3K]

Answer:

d = 40/7

Step-by-step explanation:

Solve for d:

0.544444 = 28/(9 d)

0.544444 = 49/90:

49/90 = 28/(9 d)

49/90 = 28/(9 d) is equivalent to 28/(9 d) = 49/90:

28/(9 d) = 49/90

Take the reciprocal of both sides:

(9 d)/28 = 90/49

Multiply both sides by 28/9:

Answer: d = 40/7

5 0

3 years ago