Robert wants to buy wrapping paper to cover a square-shaped painting. To determine the size of the wrapping paper needed for the

Question

4 years ago

15

Robert wants to buy wrapping paper to cover a square-shaped painting. To determine the size of the wrapping paper needed for the

painting, he adds 9 inches to each side of the painting. Robert picks out wrapping paper with a perimeter of 120 inches to wrap the square-shaped painting.
What are the side lengths of the painting and the wrapping paper?

Mathematics

2 answers:

valkas [14] · Answer 1 · 2021-12-23T03:40:12+03:00

valkas [14]4 years ago

5 0

He would need to multiplty 120 by 8=1080

kumpel [21] · Answer 2 · 2021-12-23T04:49:31+03:00

Answer:

The side length of the painting and the wrapping paper are 21 inches and 30 inches respectively.

Step-by-step explanation:

Let x be the side length ( in inches ) of the square shaped painting,

∵ After adding 9 inches in each side,

The new side length of the square = (x+9) inches, ( wrapping paper side length )

∵ Perimeter of a square = 4 × (side length)

Thus, the perimeter of the new square = 4(x+9) in

According to the question,

4(x+9) = 120

x + 9 = 30

x = 21

Hence, the side length of the square = 21 inches,

And, the side length of the wrapping paper = 30 inches