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damaskus [11]
3 years ago
14

Question 4(Multiple Choice Worth 1 points) (07.04 LC) Factor completely 49x2 − 9. (7x + 3)(7x − 3) (7x + 3)(x − 3) (7x − 3)(7x −

3) (7x − 3)(x − 3)
Mathematics
2 answers:
lana66690 [7]3 years ago
8 0

Answer:

the answer to this is

(7x-3)(7x+3)

49x^2-21x+21x-9

49x^2-9

Step-by-step explanation:

scoundrel [369]3 years ago
6 0

Answer:

A

Step-by-step explanation:

We take a look at this expression: 49x^2-9 and notice that both terms are square numbers. 49x^2=(7x)^2 and 9=3^2.

There is a specific formula that I highly recommend you memorize involving differences of squares. It states that given the difference of squares a^2-b^2, it can always be factored into (a+b)(a-b).

Here, we can apply that. In this case, a = 7x and b = 3. So:

49x^2-9=(7x)^2-3^2=(7x+3)(7x-3)

Thus, the answer is A.

Hope this helps!

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A box contains three plain pencils and 5 pens. A second box contains three colored pencils and three crayons. One item from each
worty [1.4K]

Answer:

Therefore the probability that a pen from the first box and a crayon from the second box are selected is \frac5{16}

Step-by-step explanation:

Probability:

The ratio of the number of favorable outcomes to the number all possible outcomes of the event.

Probability=\frac{\textrm{The number favorable outcomes}}{\textrm{The number all possible}}

Given that,

Three plain pencils and 5 pens are contained by the first box.

Total number of pens and pencils is =(3+5)=8

The probability that a pen is selected from the first box is

=P(A)

=\frac{\textrm{The number pens}}{\textrm{Total number of pens and pencils}}

=\frac{5}{8}

A second box contains three colored pencils and three crayons.

Total number of pencils and crayons is =(3+3)=6

The probability that a crayon is selected from the second box is

=P(B)

=\frac{\textrm{The number of crayon}}{\textrm{Total number of crayons and pencils}}

=\frac{3}{6}

Since both events are mutually independent.

The required probability is multiple of the events

Therefore the required probability is

=\frac58\times \frac36

=\frac5{16}

4 0
3 years ago
Help ASAP can u explain a little too? (pls help if u don’t know it don’t answer pls) Thank You:)
larisa [96]
Since they are similar, the dimensions are in the same ratio. L1 = 5, L2 = 15, so they are in a 3:1 ratio. So if V1 = 60, then W1×H1 = 60/5 = 12
W2 must also be 3×W1 and H2 3×H1, and
3×3 = 9. So take 12×9 (W×H1×9) ×15 (L2) = V2
V2 = 12×9×15 = 1620 cm^3

Let me know the right answer when you find out!
8 0
3 years ago
Find the value of each missing variable. y=
e-lub [12.9K]

Step-by-step explanation:

29x - 3 + 15x + 7 = 180° because these two angles are supplementary

if we add like terms

44x + 4 = 180

44x = 176 divide both sides by 44

x = 4

29x - 3 = 13y - 17 because alternate exterior angles has same measurement

since we found the value of x let's rewrite the equation

4 × 29 - 3 = 13y - 17

113 = 13y - 17

130 = 13y divide both sides by 13

10 = y

7 0
3 years ago
The braking distance, in feet of a car a Travling at v miles per hour is given.
irakobra [83]

The braking distance is the distance the car travels before coming to a stop after the brakes are applied

a. The braking distances are as follows;

  • The braking distance at 25 mph, is approximately <u>63.7 ft.</u>
  • The braking distance at 55 mph,  is approximately <u>298.35 ft.</u>
  • The braking distance at 85 mph,  is approximately <u>708.92 ft.</u>

b. If the car takes 450 feet to brake, it was traveling with a speed of 98.211 ft./s

Reason:

The given function for the braking distance is D = 2.6 + v²/22

a. The braking distance if the car is going 25 mph is therefore;

25 mph = 36.66339 ft./s

D = 2.6 + \dfrac{36.66339^2}{22} = 63.7 \ ft.

At 25 mph, the braking distance is approximately <u>63.7 ft.</u>

At 55 mph, the braking distance is given as follows;

55 mph = 80.65945  ft.s

D = 2.6 + \dfrac{80.65945^2}{22} \approx 298.35 \ ft.

At 55 mph, the braking distance is approximately <u>298.35 ft.</u>

At 85 mph, the braking distance is given as follows;

85 mph = 124.6555 ft.s

D = 2.6 + \dfrac{124.6555^2}{22} \approx 708.92 \ ft.

At 85 mph, the braking distance is approximately <u>708.92 ft.</u>

b. The speed of the car when the braking distance is 450 feet is given as follows;

450 = 2.6 + \dfrac{v^2}{22}

v² = (450 - 2.6) × 22 = 9842.8

v = √(9842.2) ≈ 98.211 ft./s

The car was moving at v ≈ <u>98.211 ft./s</u>

Learn more here:

brainly.com/question/18591940

8 0
2 years ago
Which is equivalent to cube root 8^x?
VARVARA [1.3K]

Answer:

2

Step-by-step explanation:

³√8 = 2

hope it's helpful

3 0
3 years ago
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