That would be -2 1/2 , 3 1/2
Answer:
A. (1, -2)
Step-by-step explanation:
We can substitute the variables of x and y into the inequality of
.
Let's start with A, -2 being y and 1 being x.
![-2 < - |1|](https://tex.z-dn.net/?f=-2%20%3C%20-%20%7C1%7C)
The absolute value of 1 is 1, and negating that gets us -1.
![-2 < -1](https://tex.z-dn.net/?f=-2%20%3C%20-1)
Indeed, -2 is less than -1! So A is a solution to the inequality.
Let's test the rest of them, just in case.
For B:
![-1 < -|1|](https://tex.z-dn.net/?f=-1%20%3C%20-%7C1%7C)
Absolute value of 1 is 1, negating it is -1.
![-1](https://tex.z-dn.net/?f=-1%3C-1)
-1 is EQUAL to -1, not less than it, so is not a solution to the inequality.
Let's try C.
![0 < -|1|](https://tex.z-dn.net/?f=0%20%3C%20-%7C1%7C)
Absolute value of 1 is 1, negating it is -1.
![0 < -1](https://tex.z-dn.net/?f=0%20%3C%20-1)
0 is GREATER than -1, so that is not a solution to the inequality.
Hope this helped!
Okay so I'm going to try and explain it to you as best as possible. So all they are basically telling you is to give it a name. A degree on a polynomial is the highest exponent on it and the number of terms is the number of numbers. For example: -5x^3 + 2x^2 - 7
This is a 3rd degree polynomial with 3 terms. All you have to do is look at the largest exponent and that is your degree and the number of numbers.
Answer:
b. Do not reject H0. We do not have convincing evidence that the mean weekly time spent using the Internet by Canadians is greater than 12.7 hours.
Step-by-step explanation:
Given that in a study of computer use, 1000 randomly selected Canadian Internet users were asked how much time they spend using the Internet in a typical week. The mean of the sample observations was 12.9 hours.
![H_0: \bar x =12.7\\H_a: \bar x >12,7](https://tex.z-dn.net/?f=H_0%3A%20%5Cbar%20x%20%3D12.7%5C%5CH_a%3A%20%5Cbar%20x%20%3E12%2C7)
(Right tailed test at 5% level)
Mean difference = 0.2
Std error = ![\frac{6}{\sqrt{1000} } \\=0.1897](https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B%5Csqrt%7B1000%7D%20%7D%20%5C%5C%3D0.1897)
Z statistic = 1.0540
p value = 0.145941
since p >alpha we do not reject H0.
b. Do not reject H0. We do not have convincing evidence that the mean weekly time spent using the Internet by Canadians is greater than 12.7 hours.