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vredina [299]
3 years ago
6

Y = x - 2 y = 3x + 4

Mathematics
2 answers:
faust18 [17]3 years ago
8 0

Answer:

How does it need solved? By graphing? Substitution?

Step-by-step explanation:

Andrej [43]3 years ago
4 0

Answer:

A) y = x - 2

B) y = 3x + 4   multiplying A) by -3

A) -3y = -3x +6  then adding this to B)

B) y = 3x + 4

-2y = 10

y = -5

-5 = x -2

x = -3

Step-by-step explanation:

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Sub r into area:

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7 0
3 years ago
Can someone help me get this please???
jarptica [38.1K]

Answer:

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5 0
3 years ago
(d) Given that n(§) = 96, n(A) = 50 and n(B) = 60. Find the maximum and minimum values for n(An B).
frez [133]

Step-by-step explanation:

the max. value is when the smaller set (A) is completely contained in the larger set (B).

then n(A n B) is n(A) = 50.

the set intersection between A and B cannot get bigger than that. or A gets bigger ...

after all, the intersection means it is a set of all elements that exist in BOTH sets.

but then there must be other elements besides A and B in the universal set too, because n(universal set) = 96, and n(A u B) would be only 60.

the min. value could be the empty set or 0. but because n(universal set) = 96, and n(A) + n(B) = 110 and larger than 96, it means that there have to be some shared elements. at least 110 - 96 = 14 elements.

in this case there cannot be other elements in the universal set than A and B. and n(universal set) = n(AuB) = 96.

3 0
2 years ago
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babymother [125]

Answer:  \cos 2 \theta = \dfrac{-7}{25}

Step-by-step explanation:

Given: \tan \theta = \dfrac{4}{3}  and  \pi < \theta< \dfrac{3\pi }{2}

To find: \cos 2 \theta

Now as we know

\cos 2x = \dfrac{1- \tan ^2 x}{1+ \tan ^2 x}

So we have

\cos 2 \theta = \dfrac{1-(\dfrac{4}{3} )^2}{1+(\dfrac{4}{3} )^2} \\\\\Rightarrow \cos 2 \theta = \dfrac{1- \dfrac{16}{9} }{1+ \dfrac{16}{9} } = \dfrac{\dfrac{9-16}{9} }{\dfrac{9+16}{9}} = \dfrac{-7}{25}

Therefore d. is the correct option

Hence , \cos 2 \theta = \dfrac{-7}{25}

3 0
3 years ago
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3 years ago
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