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3 years ago

Factor completely...................

Mathematics

1 answer:

defon3 years ago

3 0

Answer:

Final answer is A. $9(3x+1)(3x-2)$ .

Step-by-step explanation:

Given expression is $81x^2-27x-18$ .

$81x^2-27x-18$

$=9(9x^2-3x-2)$

We can factor that by splitting middle term into two parts then do grouping as shown below:

$=9(9x^2-6x+3x-2)$

$=9(3x(3x-2)+1(3x-2))$

$=9(3x+1)(3x-2)$

Which correctly matches with choice A. $9(3x+1)(3x-2)$ .

Hence final answer is A. $9(3x+1)(3x-2)$ .

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(5.2c-7.35)+(-3.9c+2.65)

Effectus [21]

Answer:

1.3c - 4.69

Step-by-step explanation:

5.2 - 3.9 = 1.3

2.65 - 7.35 = -4.69

4 0

3 years ago

If the ship can travel to either dock, which dock would be closest? Explain your answer. Michael’s dock would be closer because

Greeley [361]

Answer : Michael’s dock would be closer because the angle opposite is smaller

Michael and Jacob are standing on two docks that are 20 miles apart. They are watching a ship that is out in the ocean. The angle between the dock and the line connecting Michael and the ship is 48°, and the angle between the other dock and the line connecting Jacob and the ship is 37°.

Explanation:

the angle between the other dock and the line connecting Jacob and the ship is 37°. The side opposite to angle 37 will be smaller. The distance between Michael and Ship will be smaller than Jacob and ship.

So Michael’s dock would be closer because the angle opposite is smaller.

7 0

3 years ago

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4x^2 y+8xy'+y=x, y(1)= 9, y'(1)=25

jarptica [38.1K]

Answer with explanation:

$\rightarrow 4x^2y+8x y'+y=x\\\\\rightarrow 8xy'+y(1+4x^2)=x\\\\\rightarrow y'+y\times\frac{1+4x^2}{8x}=\frac{1}{8}$

--------------------------------------------------------Dividing both sides by 8 x

This Integration is of the form ⇒y'+p y=q,which is Linear differential equation.

Integrating Factor

$=e^{\int \frac{1+4x^2}{8x} dx}\\\\e^{\log x^{\frac{1}{8}+\frac{x^2}{2}}\\\\=x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}$

Multiplying both sides by Integrating Factor

$x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}\times [y'+y\times\frac{1+4x^2}{8x}]=\frac{1}{8}\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}\\\\ \text{Integrating both sides}\\\\y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=\frac{1}{8}\int {x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}} \, dx \\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=\int {x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}} \, dx\\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=-[x^{\frac{9}{8}}]\times\frac{ \Gamma(0.5625, -x^2)}{(-x^2)^{\frac{9}{16}}}\\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=(-1)^{\frac{-1}{8}}[ \Gamma(0.5625, -x^2)]+C-----(1)$

When , x=1, gives , y=9.

Evaluate the value of C and substitute in the equation 1.

6 0

3 years ago

Lynn rents a luxury car at the Edmonton Internacional Airport. She wants a nice

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3 years ago

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Sam used 6 loaves of elf bread

stellarik [79]

Sam used 6 loaves of elf bread???

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3 years ago

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