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Anastasy [175]
3 years ago
13

Lynn rents a luxury car at the Edmonton Internacional Airport. She wants a nice

Mathematics
2 answers:
Aneli [31]3 years ago
6 0

Answer:

Step-by-step explanation:

Looking at the table,

a) the standard daily rate for a luxury car is $70. Since Lynn wants to rent the luxury car for 3 days, it means that the standard rate for 3 days would be

3 × 70 = $210

She figures she will put on about 400 km during the three

days. The cost of renting the luxury car per kilometer(mileage) is 30 cents. Therefore, the cost for 400 kilometers would be

400 × 30 = 12000 cents.

Converting 12000 cents to dollars, it becomes

12000/100 = $120

Total cost of renting the luxury car would be

120 + 210 = $330

b) the daily cost of the unlimited mileage daily for the luxury car is $105

Total cost of renting the luxury car for 3 days would be

105 × 3 = $315

c) the standard daily rate is better because it is cheaper

Tpy6a [65]3 years ago
3 0
A. $330 for the 3 day trip if she does not go over 400 km
b $315 for the cost of the Unlimited Mileage plan.
c. the Unlimited Mileage plan would save you $15 compared to the Standard Daily Rate.
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Answer:

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IgorLugansk [536]

Answer:

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Whole proccess above!

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