Let us assume that the number of beige tiles bought by Susan = B
Number of red tiles bought by Susan = R
Number of navy-blue tiles bought by Susan =N
Number of tiles bought altogether = 435
Now from the given question we know:
Number of red tiles bought is 25 more than the number of beige tiles.
So
R = 25 + B
Number of navy blue tiles bought is 3 times that of the number of beige tile bought
So
N = 3B
We already know that the total number of tiles bought is 435
Hence
B + R + N = 435
B + (25 + B) + 3B = 435
5B + 25 = 435
5B = 435 -25
5B = 410
B = 82
R = 25 + B
= 25 + 82
= 107
N = 3B
= 3 * 82
= 246
So the number of Beige tiles bought by Susan = 82
The number of red tiles bought by Susan = 107
The number of navy-blue tiles bought by Susan = 246
Answer:
C
Step-by-step explanation:
Answer:
The system of equations is:
x + y = 15
xy = 15
Step-by-step explanation:
solve the first for y and substitute in the second:
y = 15-x
x(15-x) = 15
15x - x� = 15
15x - x� - 15 = 0
-x� + 15x - 15 = 0
x� - 15x + 15 = 0
