Let x = software program
Let y = video game
x < 200 ; y < 300
x + y < 425
50x ; 35y
x = 200 ; y = 225
50(200) + 35(225) = 10,000 + 7,875 = 17,875
x = 125 ; y = 300
50(125) + 35(300) = 6,250 + 10,500 = 16,750
x = 175 ; y = 250
50(175) + 35(250) = 8,750 + 8,750 = 17,500
It is more profitable to maximize production of software program when working within the limits provided.
Answer:
$93.75
Step-by-step explanation:
Answer:
There should be a crown that you can press which represents a brainiest
Step-by-step explanation:
ANSWER
Find out the how much fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze .
To proof
let us assume that the fluid should be drained and replaced with pure antifreeze be x .
As given
A radiator contains 10 quarts of fluid, 30% of which is antifreeze.
Now write 30% in the decimal form

Now write 60% in the decimal form

After drained and replaced the fluid with pure antifreeze than the quantity becomes = ( 10 - x )
The quantity of antifreeze is

The fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze .
than the equation becomes

solyving
100x +300 - 30x = 600
70x = 300

x = 4.28 quarts (approx)
Hence 4.28 quarts (approx) fluid should be drained and replaced with pure antifreeze so that the new mixture is 60% antifreeze .
Therefore the option (c.) is correct .