What is 0.000084 sceincetific notation help me out and can u explain how to get the answer

Mathematics

2 answers:

damaskus [11]3 years ago

7 0

Answer:

8.4 x 10'5

Step-by-step explanation:

move the decimal point to make a number between 1 and 9.9. so 8.4. count how many times the decimal point moves. that's the power of 10

Kaylis [27]3 years ago

6 0

Answer:

.84 x 10 ^4

Step-by-step explanation:

hope this helps!!!

i just got done with these, please mark brainliest

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Nuts.com sells raw almonds for $10 per pound and roasted pistachios for $12 per pound. Christopher spends $70, before taxes and

galben [10]

Answer:

second equation

Step-by-step explanation:

10a + 12p = 70 (10 goes with almonds [a], 12 goes with pistachios[p], $10 and $12 is price per pound and $70 is total price, so that's why its = to 70)

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valina [46]

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What are the points of discontinutity y=(x-3)/x^2-12x+27

madreJ [45]

Answer:

$(3, -\frac{1}{6})$

Step-by-step explanation:

We can rewrite the equation as

$y = \frac{x - 3}{(x - 3)(x - 9)}$

Notice that we have $x - 3$ in both the numerator and the denominator, so it looks like we can divide it out. However, what if $x - 3$ is $0$ ? Then we would have $y = \frac{0}{0 \times (x - 9)} = \frac{0}{0}$ , which is undefined. So although it looks like the numerator and denominator can be simplified, the resulting function we would get from simplification would not have the same behavior as this one (since such a function would be defined for $x = 3$ , but this one is not).

A point of discontinuity refers to a particular point which is included in the simplified function, but which is not included in the original one. In this case, the point which is not included in the unsimplified function is at $x = 3$ . In the simplified version of the function, if we plug in $x = 3$ , we get

$y = \frac{1}{((3) - 9)} = -\frac{1}{6}$

So the point $(3, -\frac{1}{6})$ is our only point of discontinuity.

It's also important to distinguish between specific points of discontinuity and vertical asymptotes. This function also has a vertical asymptote at $x = 9$ (since it causes the denominator to be 0), but the difference in behavior is that in the case of the asymptote, only the denominator becomes 0 for a specific value of $x$