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Tresset [83]
3 years ago
10

What is the lcm of 28 and 42

Mathematics
1 answer:
Anastasy [175]3 years ago
6 0
84.
28x3 = 84
42x2 = 84
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What is the area of a sector of a circle with a radius of 6 inches and formed by a central angle that measures 90°?
trapecia [35]

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What is the midpoint of the line segment with endpoints (1,-6) and (-3,4)?
kirill115 [55]

Answer:

(-1,-1)

Step-by-step explanation:

To find the x coordinate of the midpoint, add the x coordinates of the endpoint and divide by 2

(1+-3)/2 = -2/2 = -1

To find the y coordinate of the midpoint, add the y coordinates of the endpoint and divide by 2

(-6+4)/2 = -2/2 = -1

(-1,-1)

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3 years ago
What is 7/10+20/100?
Firdavs [7]
9/10. make the bottom numbers the same to add fractions. you can do that by multiplying 7/10 by 10/10.

70/100 + 20/100 = 90/100

90/100 = 9/10

you can also reduce 20/100 to 2/10.

7/10 + 2/10 = 9/10
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Solve each system by eliminating one of the variables by addition or<br> subtraction.
Vlad1618 [11]

Answer:

1) x- y = 8

x + y = 12

eliminate one variable by adding the equations

2x = 20

divided by 2 on both sides

x = 10

substitute the value of x in the equation 1

10 - y = 8

-y = 8- 10

y =2

[x , y]

[10 , 2]

2) 2x - y = 4

3x + y = 6

eliminate one variable by adding the equations

5x = 10

x = 2

substitute the value of x in the equation

2(2) - y = 4

4 - y = 4

y = 0

[x ; y]

[2; 0]

3) x + 2y = 10

x + 4y = 14

multiply equation 1 by - 1

-x -2y = -10

x + 4y = 14

eliminate one variable by adding the equations

2 y = 4

y = 2

substitute the value of y in the equation 1

x + 2(2) = 10

x + 4 = 10

x = 6

[x ; y]

[6 ; 2]

4 ) 3x + y = 9

y = 3x + 6

simplify the expression

3x + y = 9

- 3x + y = 6

eliminate one variable by adding the equations

2y = 15

y = 15/2

substitute the value of y in equation 1

3x + 15/ 2 = 9

3x = 3/2

x = 1/2

[x ; y]

[1/2 ; 15/ 2]

5) 4x + 5y = 15

6x - 5y = 18

eliminate one variable by adding the equations

10 x = 33

× = 33/10

substitute the value of x in equation I

4 (33/10) + 5y = 15

66/5 + 5y =15

5y = 9/5

y = 9/25

[x ; y]

[33/10 ; 9/25]

6) 5x = 7y

x + 7y = 21

in equation I move the variable to the left

5x - 7y = 0

x + 7 y = 21

eliminate one variable by adding the equations

6x = 21

x = 7/2

substitute the value of x in the equation

5(7/2) = 7y

35/2 = 7y

5/2 = y

[x ; y ]

[7/2 ; 5/2 ]

4 0
3 years ago
E perimeter of a rectangle is 28 meters, and the diagonal is 10 meters,<br><br>what is the area?​
dedylja [7]

Answer:

The rectangle's area is 48 square meters

Step-by-step explanation:

Recall that the perimeter of a rectangle of base b and height h is given by the formula:

Perimeter = 2 b + 2 h

we know that the perimeter is 28 meters, then we can create our first equation;

2 b + 2 h = 28

which means:

2 (b + h) = 28

b + h = 28/2

b + h = 14

the tell us that the diagonal is 10 meters, so we use the Pythagorean theorem to write a second equation using the rectangle's base, height, and diagonal (which form in between the three a right angle triangle where the hypotenuse is the rectangle's diagonal:

h^2+b^2=10^2=100

So, we can use the equation :  b + h = 14 to write one variable in terms of the other one and use it as substitution in the second (quadratic) equation:

h = 14 - b

then:

h^2+b^2=100\\(14-b)^2+b^2=100\\14^2-28\,b+b^2+b^2=100\\2\,b^2-28\,b+196-100=0\\2\,b^2-28\,b+96=0\\b^2-14\,b+48=0

which we have reduced at the end by dividing both sides by 2.

we can use factoring to solve these equation;

b^2-14\,b+48=0\\b^2-6\,b-8\,b+48=0\\b\,(b-6)-8\,(b-6)=0\\(b-6)\,(b-8)=0

Se we find two possible solutions: b = 6 m or b = 8 m

If we call b = 8 m, then the height becomes h = 14 - (8) = 6 m

and viceversa.

So a rectangle with such dimensions will render an area that equals :

Area = b x h = 8 x 6 = 48 square meters.

3 0
3 years ago
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