Question

If r= - square root2 and a^5= 32square root2, what is the first term of the sequence?

Answer 1

Answer:

8√2

Step-by-step explanation:

r=-√2

a5=32√2

an=a1(r)^{n-1}

32√2=a1(-√2)^{5-1}=a1×(-√2)^4=a1×4

$a1=\frac{32\sqrt{2}}{4}=8\sqrt{2}$