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Ilia_Sergeevich [38]
3 years ago
6

If r= - square root2 and a^5= 32square root2, what is the first term of the sequence?

Mathematics
1 answer:
Elena-2011 [213]3 years ago
8 0

Answer:

8√2

Step-by-step explanation:

r=-√2

a5=32√2

an=a1(r)^{n-1}

32√2=a1(-√2)^{5-1}=a1×(-√2)^4=a1×4

a1=\frac{32\sqrt{2}}{4}=8\sqrt{2}

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Given: △ABC, E∈ AB m∠ABC=m∠ACE AB=34, AC=20 Find: AE
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AE = 11.76 units

Step-by-step explanation:

For better understanding of the solution, see the attached figure :

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In ΔABC and ΔACE,

m∠ABC = m∠ACE ( Given )

∠A = ∠A    ( Common angle for both the triangles )

By AA postulate of similarity of triangles, ΔABC ~ ΔACE

So, proportion of the corresponding will be equal.

\implies \frac{AC}{AB}=\frac{CE}{BC}=\frac{AE}{AC}\\\\\implies\frac{AC}{AB}=\frac{AE}{AC}\\\\\implies\frac{20}{34}=\frac{AE}{20}\\\\\implies AE=\frac{20\times 20}{34}\approx 11.76

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