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Ostrovityanka [42]
3 years ago
12

Simplify the following cos(-x)tanx

Mathematics
1 answer:
RSB [31]3 years ago
8 0
\bf \textit{symmetry identites}\\\\
cos(-\theta)=cos(\theta)\\\\
-----------------------------\\\\
cos(-x)tan(x)\implies cos(-x)\cdot \cfrac{sin(x)}{cos(x)}\\\\\\ cos(x)\cdot \cfrac{sin(x)}{cos(x)}\implies sin(x)
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The store paid $2. 70 for a book and sold it for $6. 20. What is the profit as a percent?.
bogdanovich [222]

Answer:

profit = 129.63% (to the nearest hundredth) as a percent of the price the store paid for the book

Step-by-step explanation:

Use the percentage change formula:

percent change = [ (difference between the initial value and the final value) ÷ initial value] x 100

= [ (6.20 - 2.70) ÷ 2.70 ] x 100

= [ 3.5 ÷ 2.70 ] x 100

= 37/27  x 100

= 129.6296296...

= 129.63% (to the nearest hundredth)

5 0
2 years ago
Find the area and perimeter of the rectangle whose sides are lengths 2x + 3 and 4x.
mote1985 [20]

The answer to this problem is 3(2x+1)

7 0
3 years ago
The coordinates of three vertices of a triangle are (3, 5), (-1, 5), and (-1, -3). What is the area of the triangle?
Marina86 [1]
If you would graph the triangle, one of the legs would be 8 and another would be 5 and the area of a triangle is bxh/2 so the equation is 8x5/2=20un².
Hope this helped! :)
7 0
3 years ago
Please help me this only works once
Sphinxa [80]

Answer:

A

Step-by-step explanation:

all can divide by 4

12/4 = 3

16/4 = 4

8 0
3 years ago
Read 2 more answers
Given f (x ) = x^2 + 3x + 2 and g (x ) = x + 1, perform the indicated operations.
Nana76 [90]

Answer:

(i) (f - g)(x) = x² + 2·x + 1

(ii) (f + g)(x) = x² + 4·x + 3

(iii) (f·g)(x) = x³ + 4·x² + 5·x + 2

Step-by-step explanation:

The given functions are;

f(x) = x² + 3·x + 2

g(x) = x + 1

(i) (f - g)(x) = f(x) - g(x)

∴ (f - g)(x) = x² + 3·x + 2 - (x + 1) = x² + 3·x + 2 - x - 1 = x² + 2·x + 1

(f - g)(x) = x² + 2·x + 1

(ii) (f + g)(x) = f(x) + g(x)

∴ (f + g)(x) = x² + 3·x + 2 + (x + 1) = x² + 3·x + 2 + x + 1 = x² + 4·x + 3

(f + g)(x) = x² + 4·x + 3

(iii) (f·g)(x) = f(x) × g(x)

∴ (f·g)(x) = (x² + 3·x + 2) × (x + 1) = x³ + 3·x² + 2·x + x² + 3·x + 2 = x³ + 4·x² + 5·x + 2

(f·g)(x) = x³ + 4·x² + 5·x + 2

7 0
3 years ago
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