solution:
we know that ,
u.v = ΙuΙ ΙvΙcosθ
here,
θ =60° (since the given triangle is equilateral triangle)
u.v = ΙuΙ ΙvΙcos60°
= 1 x 1 x 1/2
u.v = 1/2
now, u.w = ΙuΙ ΙwΙcosθ
= ΙuΙ x cos(60x2)
u.w = -1/2
Answer:
Step-by-step explanation:
Excellent 43.0000
Answer 8747744748848833773737374758
An outlier is a datapoint outside of the first or third quartile +/- 1.5 the inter quartile range
25 33 39 40 41 41 45 46 48 49 51 52 67 73 79
46 is at the center-> median
everything left of it:
25 33 39 40 41 41 45
40 at center=Q1
right of Q2:
48 49 51 52 67 73 79
52 at center=Q3
IQR=Q3-Q1=52-40=12
Q1-1.5*IQR=40-1.5*12=40-18=22
Q3+1.5*IQR=52+1.5*12=52+18=60
so everything <22 or >60 are outliers
so 67,73 and 79 are outliers
