Who here is a homo????

Mathematics

1 answer:

Natasha_Volkova [10]3 years ago

6 0

No me,Almost no one in the world is a homo,there were homo more than 1 millions of years

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ryzh [129]

so what u gotta do in this add and multiply everything up like monday she worked before and wor and during work, then tuesday she worked twice as much as monday then u gotta add and multiply everythin up, same thing all over again, then you get ur answer, nlow this app is too help you, i helped you, im not goona give ur answer, ur gonna give the answer to ur selfe, now i dont have time rn to answer it and if i did i would help you n answer but u gotta do ur work, have a great daay!

3 0

3 years ago

taurus [48]

Answer:

$x^2 - 2x + 10$ , option B

Step-by-step explanation:

Complex numbers:

The most important relation that involves complex numbers is given by:

$i^2 = -1$

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this question:

The solutions are:

$x_1 = 1 - 3i, x_2 = 1 + 3i$

We have to find the polynomial. All option have $a = 1$ . So

$(x - (1 - 3i))(x - (1 + 3i)) = x^2 - x(1 + 3i) - x(1 - 3i) + (1 - 3i)(1 + 3i) = x^2 - x -3ix - x + 3ix + 1^2 - (3i^2) = x^2 - 2x + 1 - 9i^2 = x^2 - 2x + 1 - 9(-1) = x^2 - 2x + 10$