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3 years ago

15

Find the nonpermissible replacement for a in this expression 7/6a

1 answer:

vredina [299]3 years ago

6 0

The correct answer for the exercise shown above is:

zero (0)

The explanation is shown below:

1. You have the following expression given in the problem above:

7/6a

2. By definition, <span>the nonpermissible replacement for a is the value that make the denominator equal to zero.

3. Keeping this on mind, you have:

7/6a=7/6(0)=7/0

Therefore, as you can see, the answer is: zero (a=0).

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What is the best estimate of 11 1/5÷2 3/4

likoan [24]

Answer:4

Step-by-step explanation:

5 0

3 years ago

Professor Halen teaches a College Mathematics class. The scores on the midterm exam are normally distributed with a mean of 72.3

lbvjy [14]

Answer:

14.63% probability that a student scores between 82 and 90

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 72.3, \sigma = 8.9$

What is the probability that a student scores between 82 and 90?

This is the pvalue of Z when X = 90 subtracted by the pvalue of Z when X = 82. So

X = 90

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{90 - 73.9}{8.9}$

$Z = 1.81$

$Z = 1.81$ has a pvalue of 0.9649

X = 82

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{82 - 73.9}{8.9}$

$Z = 0.91$

$Z = 0.91$ has a pvalue of 0.8186

0.9649 - 0.8186 = 0.1463

14.63% probability that a student scores between 82 and 90

3 0

3 years ago

A vase in the shape of an oblique cylinder has the dimensions shown. What is the volume of the vase?

fenix001 [56]

The image is missing so i have attached it.

Answer:

Volume = 1.5 litres

Step-by-step explanation:

Using pythagoras theorem, we can get the height (h) of the cylinder

14² + h² = 17²

h² = 289 - 196

h = √93

Now, volume of a cylinder is;

V = πr²h

In the image, r = diameter/2 = 14/2 = 7cm

Thus,

V = π × 7² × √93

V = 1485 cm³

Now, 1 litre = 1000 cm³

Thus, volume = 1485/1000 = 1.485 litres ≈ 1.5 litres

5 0

3 years ago

Read 2 more answers

Solve 5r2 – 12 = 68. {±4} {±5} {±3} {±6}

sashaice [31]

Hey there!

Assuming you meant

$5r^2 - 12 = 68$

If so, follow these steps so it can be a little bit easier to solve

Firstly, we have to $add$ by $12$ on each of your sides

$5r^2 -12 +12 \\ \\ 68 + 12$

$5r^2 = 5r^2 \\ \\ 68 + 12 = 80$

We get: $5r^2 =80$

Now, we have $divide$ by $5$ on each of your sides

$\frac{5r^2}{5} = \frac{80}{5}$

$\frac{80}{5} = 16$

We get: $r^2 = 16$

$r =$ ± $\sqrt{16}$

Therefore , your answer is: $r =$ ± $4$

Good luck on your assignment and enjoy your day!

~ $LoveYourselfFirst:)$

3 0

3 years ago

An item was sold at a loss of 20%. Had it been sold for Rs 3000more then the profit would have been 10%. What is the cost price

vagabundo [1.1K]

Answer:

Cost Price = Rs 10000

Step-by-step explanation:

Assume:

Cost of the item = x

Item was sold at a loss of 20%:

Loss = 20% of x = 0.2x

Item sold = x - 0.2x = 0.8x

Item sold at a profit of 10%:

Profit = 10% of x = 0.1x

item sold = x + 0.1x = 1.1x

Solve:

Difference = 1.1x - 0.8x = 0.3x

0.3x = Rs 3000

x = Rs 3000 ÷ 0.3

x = Rs 10000

3 0

3 years ago