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3 years ago

15

Find the nonpermissible replacement for a in this expression 7/6a

1 answer:

vredina [299]3 years ago

6 0

The correct answer for the exercise shown above is:

zero (0)

The explanation is shown below:

1. You have the following expression given in the problem above:

7/6a

2. By definition, <span>the nonpermissible replacement for a is the value that make the denominator equal to zero.

3. Keeping this on mind, you have:

7/6a=7/6(0)=7/0

Therefore, as you can see, the answer is: zero (a=0).

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40 points to the person who answers

bezimeni [28]

Hey there!

So, here is a visual of the graph.

~ ~ ~ ~ ~

~ ~ ~ ~ 5

~ ~ ~ 4

~ ~ 3

~ 2

1

The definition of symmetric is that there are two equal parts. This would not cut in half equal so it is not symmetric.

The peak is at 1, since 5 is the highest number of dots. So, the correct answer would be:

"It is not symmetric and has a peak at 1." <=== third choice

I hope this helps!

~kaikers

4 0

3 years ago

What is the answer to this equation |x + 1| = 6

djverab [1.8K]

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3 years ago

Alice walks 6 over 10 mile ever day. How far does alice in 5 days?

leva [86]

Answer:

3 miles

Step-by-step explanation:

6/10x5=30/10

30/10=3

5 0

3 years ago

Match each term with the part of the expression 9m4−12m−6−12 it best describes. All terms will be used ONLY once.

RideAnS [48]

Answer:

see below...

Step-by-step explanation:

-12=constant [# doesn't change]

4=degree [exponent]

-6m= term [variable or 3]

9=coefficient [first #]

4 0

3 years ago

Given g(x)=3/x^2+2x find g^-1(x)

attashe74 [19]

Answer:

Inverse function is: $g^{-1}x=\frac{-x\pm\sqrt{x(x+3)}}{x}$

Step-by-step explanation:

Given Given the function $g(x)=\frac{3}{x^2+2x}$

we have to find the inverse function of g

To find inverse following steps are:

Step 1: Replace g(x) with y

Step 2: Replace every x with a y and every y with x

Step 3: Solve the equation obtained from Step 2 for y.

Step 4: Replace y with g−1(x).

$g(x)=\frac{3}{x^2+2x}$

To find the inverse, let $y=\frac{3}{x^2+2x}$

Now, solve for x

$y(x^2+2x)=3$

$yx^2+2yx-3=0$

$x=\frac{-2y\pm\sqrt{4y^2-4y(-3)}}{2y}$

$x=\frac{-2y\pm\sqrt{4y^2+12y}}{2y}$

$x=\frac{-2y\pm2\sqrt{y^2+3y}}{2y}$

$x=\frac{-y\pm\sqrt{y(y+3)}}{y}$

Replace every x with a y and every y with x , we get

$y=\frac{-x\pm\sqrt{x(x+3)}}{x}$

Replace y with g−1(x).

$g^{-1}x=\frac{-x\pm\sqrt{x(x+3)}}{x}$

So inverse function is: $g^{-1}x=\frac{-x\pm\sqrt{x(x+3)}}{x}$

6 0

3 years ago