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Alecsey [184]
3 years ago
15

Using the formula C = 2πr, find the circumference of a circle with diameter of 28 inches. Round your answer to the nearest inch.

A. 88 in. B. 44 in. C. 28 in. D. 56 in.
Mathematics
2 answers:
Stolb23 [73]3 years ago
8 0
The formula given to us relates circumference with radius but we are given diameter instead. good thing we know that diameter is twice the length of radius so if diameter=28, the radius=14. therefore, using our formula, we can find the circumference:
C = 2(pi)(14)
C = 87.96
and this answer is close to 88 so the answer is A

let me know if you have any questions!!!

LiRa [457]3 years ago
5 0
Hi there! C=πd=π*28=87.96459, 87.96 rounded to the nearest tenth would be 88. Therefore, your answer is A. 88 in
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Y_Kistochka [10]
Scale : 1 cm = 2.5 ft

1 cm = 2.5 ft
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8 0
3 years ago
Write the equation for:
xenn [34]

Answer:

\frac{1}{2} x +x = 2 (x-4)

Step-by-step explanation:

Suppose number is x

Following equation can be written from question statement

\frac{1}{2} x +x = 2 (x-4)

Simplifying it further

\frac{3}{2} x = 2x-8

\frac{3}{2} x -2x=-8

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7 0
2 years ago
Find the sum of the first n terms.
Sunny_sXe [5.5K]
S(8)=((100×(1−(50÷100)^(8))÷(1−50÷100)))
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5 0
3 years ago
I need the answers for both a and b so thats why 61 points are up for grab
kodGreya [7K]

Answer:

Step-by-step explanation:

From the picture attached,

a). Triangle in the figure is ΔBCF

b). Since, L_1 and L_2 are the parallel lines and m is a transversal line,

   m∠FBC = m∠BFG [Alternate interior angles]

   Since,  L_1 and L_2 are the parallel lines and n is a transversal line,

   m∠BCF = m∠CFE [Alternate interior angles]

   By triangle sum theorem in ΔBCF

   m∠FBC + m∠BCF + m∠BFC = 180°

   From the properties given above,

   m∠BFG + m∠CFE + m∠BFC = 180°

   m∠GFE = 180°

Therefore, angle GFE is the straight angle that will be useful in proving that the sum of the measures of the interior angles of the triangle is 180°.

5 0
2 years ago
50 PTS ANSWER ALL <3333333
11Alexandr11 [23.1K]

QUESTION 33

The length of the legs of the right triangle are given as,

6 centimeters and 8 centimeters.

The length of the hypotenuse can be found using the Pythagoras Theorem.

{h}^{2}  =  {6}^{2}  +  {8}^{2}

{h}^{2}  = 36+ 64

{h}^{2}  = 100

h =  \sqrt{100}

h = 10cm

Answer: C

QUESTION 34

The triangle has a hypotenuse of length, 55 inches and a leg of 33 inches.

The length of the other leg can be found using the Pythagoras Theorem,

{l}^{2}  +  {33}^{2}  =  {55}^{2}

{l}^{2}  =  {55}^{2}  -  {33}^{2}

{l}^{2}  = 1936

l =  \sqrt{1936}

l = 44cm

Answer:B

QUESTION 35.

We want to find the distance between,

(2,-1) and (-1,3).

Recall the distance formula,

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Substitute the values to get,

d=\sqrt{( - 1-2)^2+(3- - 1)^2}

d=\sqrt{( - 3)^2+(4)^2}

d=\sqrt{9+16}

d=\sqrt{25}

d = 5

Answer: 5 units.

QUESTION 36

We want to find the distance between,

(2,2) and (-3,-3).

We use the distance formula again,

d=\sqrt{( - 3-2)^2+( - 3- 2)^2}

d=\sqrt{( - 5)^2+( - 5)^2}

d=\sqrt{25+25}

d=\sqrt{50}

d=5\sqrt{2}

Answer: D

8 0
2 years ago
Read 2 more answers
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