What is the slop of a line perpendicular to the line whose equation is 4x+6y=108. Reduce your answer
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Answer:
Step-by-step explanation:
Slope-intercept form: y = mx + b
Slope formula:
Given points: (3, -7), (7, 2)
(3, -7) = (x1, y1)
(7, 2) = (x2, y2)
To write the equation in slope-intercept form, we need to find the slope(m) and the y-intercept(b) of the equation.
First, let's find the slope. To do this, input the given points into the slope formula:
Simplify:
2 - (-7) = 2 + 7 = 9
7 - 3 = 4
The slope is .
To find the y-intercept, input the slope and one of the given points(in this example I'll use point (7, 2)) into the equation and solve for b:
The y-intercept is .
Now that we know the slope and the y-intercept, we can write the equation: