Answer:
- the domain is [0,129]
- 112 mm
- 1942
Step-by-step explanation:
1. The function is good for years 1880 to 2009, 0 to 129 years after 1880. Values of x can be anything in the domain [0, 129].
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2. 1950 -1880 = 70. The year 1950 corresponds to x=70, so the function tells us the water level rose ...
f(70) = 1.6·70 = 112 . . . . . mm
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3. We want to find x when f(x) = 100. That will be the solution to ...
100 = 1.6x
100/1.6 = x = 62.5
Then 62.5 years after 1880 is year 1942.5. The water level was 100 mm higher than in 1880 in the year 1942.
Answer:
Hope it helps....!!!!!
Step-by-step explanation:
AB = c = 38
BC = a = 29
AC = b
Angle ABC = 63 degrees
Solving for AC "b":
Cosine rule: c^2 = a^2 * b^2 -2ab * cos C
38^2 = 29^2 * b^2 - (2* 29) * b * (cos 38)
1444 = 841 * b^2 - 58 * b * 0.955
(1444 + 58)/0.955 = b^2 * b
1572.77486911 = b^3
11.62935 = b
11.63 = b (rounded to two decimal places)
Now solving for angle A:
Sine rule: a/sinA = b/sinB
29/sinA = 11.63/sin(63)
sinA/29 = sin(63)/11.63
sin A = (sin(63)/11.63) * 29
sin A = 0.41731
A = sin^-1 (0.41731)
A = 24 degrees 39 minutes 53 seconds
Now solving for angle C:
Sine rule: c/sinC = b/sinB
38/sinC = 11.63/sin(63)
sinC/38 = sin(63)/11.63
sin C = (sin(63)/11.63) * 38
sin C = 0.54682
C = sin^-1 (0.54682)
C = 33 degrees 8 minutes 56 seconds
Answer:
5 gallons would be left in the tank after 4 hours.
Step-by-step explanation:
(how much is t hours)
Answer:
83
Step-by-step explanation:
f(x) = 7x - 1
Put x as 12.
f(12) = 7(12) - 1
f(12) = 84 - 1
f(12) = 83
Answer:
f (x) = 2x² + 6x - 20
<u>Brainliest Please!!!</u>
