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pochemuha
3 years ago
5

Answer ASAP DO NOT ANSWER UNTIL IMAGE IS SEEN

Mathematics
1 answer:
Alja [10]3 years ago
7 0
1 vinegar to 1/2 of oil  is equivalent to 2 parts of vinegar to 1 part of oil
equation is y =  2x

the second option is the correct one.
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7TH GRADE MATH- Please solve the one with the star- question 18. Thank you!
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27.5 pages per hour.

Step-by-step explanation:

Santino read 5\frac{1}{2} pages in 12 minutes

In 60 minutes he read:

\frac{60}{12} × 5.5 = 27.5 pages

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The following lines are parallel.<br> 4x + 2y = 8 and y = 2x + 4<br> True<br> False
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4 years ago
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Which expression represents the slope of a line that passes through the points (0, 0) and (x, y)
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Yuhh the answers c dawhggg trus me i just did the same thing lawl!

Step-by-step explanation:

6 0
3 years ago
The mean height of women in a country (ages 20-29) is 64 4 inches A random sample of 50 women in this age group is selected What
Simora [160]

Answer:

0.0721 = 7.21% probability that the mean height for the sample is greater than 65 inches.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 64.4 inches, standard deviation of 2.91

This means that \mu = 64.4, \sigma = 2.91

Sample of 50 women

This means that n = 50, s = \frac{2.91}{\sqrt{50}}

What is the probability that the mean height for the sample is greater than 65 inches?

This is 1 subtracted by the p-value of Z when X = 65. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{65 - 64.4}{\frac{2.91}{\sqrt{50}}}

Z = 1.46

Z = 1.46 has a p-value of 0.9279

1 - 0.9279 = 0.0721

0.0721 = 7.21% probability that the mean height for the sample is greater than 65 inches.

8 0
3 years ago
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