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Thepotemich [5.8K]
4 years ago
10

Evaluate 7m+2n-8p/n m=4, n=2, and p=1.5

Mathematics
1 answer:
Firlakuza [10]4 years ago
4 0

Steps to solve:

7m + 2n - 8p/n

~Substitute

7(4) + 2(2) - 8(1.5)/2

~Simplify

28 + 4 - 12/2

~Simplify

28 + 4 - 6

~Add

32

~Subtract

26

Best of Luck!

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Multiply.<br><br> −3 2/3⋅(−2 1/4) ?<br><br><br> −8 1/4<br><br> −6 1/6<br><br> 6 1/6<br><br> 8 1/4
Temka [501]

Answer:

D

Step-by-step explanation:

-3 2/3 * -2 1/4

~Turn into improper fractions

-11/3 * -9/4

~Multiply both numerators and denominators

99/12

~Turn into a mixed number

8 3/12

~Simplify

8 1/4

Best of Luck!

6 0
3 years ago
Read 2 more answers
How many ways can a cook arrange 7 of 10 spice jars on a spice rack?
Tamiku [17]

Answer:

equation below

Step-by-step explanation:

7!

7!(10-7)!

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3 years ago
Read 2 more answers
A fair coin is tossed three times and the events A, B, and C are defined as follows: A: \{ At least one head is observed \} B: \
Yanka [14]

Answer:

a) P(A)=0.875

b) \text{P(A or B)}=0.875

c) \text{P((not A)  or B  or (not C))}=0.625

Step-by-step explanation:

Given : A fair coin is tossed three times and the events A, B, and C are defined as follows: A: At least one head is observed, B: At least two heads are observed, C: The number of heads observed is odd.

To find : The following probabilities by summing the probabilities of the appropriate sample points ?

Solution :

The sample space is

S={HHH,HHT,HTT,HTH,TTT,TTH,THH,THT}

n(S)=8

A: At least one head is observed

i.e. A={HHH,HHT,HTT,HTH,TTH,TTH,THH,THT}

n(A)=7

B: At least two heads are observed

i.e. B={HHH,HTT,TTH,THT}

n(B)=4

C: The number of heads observed is odd.

i.e. C={HHH,HTT,THT,TTH}

n(c)=4

a) Probability of A, P(A)

P(A)=\frac{n(A)}{n(S)}

P(A)=\frac{7}{8}

P(A)=0.875

b) P(A or B)

Using formula,

\text{P(A or B)}=P(A)+P(B)-\text{P(A and B)}

\text{P(A or B)}=\frac{n(A)}{n(S)}+\frac{n(B)}{n(S)}-\frac{\text{n(A and B)}}{n(S)}

\text{P(A or B)}=\frac{7}{8}+\frac{4}{8}-\frac{4}{8}

\text{P(A or B)}=\frac{7}{8}

\text{P(A or B)}=0.875

(c) P((not A)  or B  or (not C))

A={HHH,HHT,HTT,HTH,TTH,TTH,THH,THT}

not A = {TTT} = 1

B={HHH,HTT,TTH,THT}

C={HHH,HTT,THT,TTH}

not C = {HHT,HTH,THH,TTT} = 4

So, not A or B or not C = {HHH,HHT,HTH,THH,TTT}=5

\text{P((not A)  or B  or (not C))}=\frac{5}{8}

\text{P((not A)  or B  or (not C))}=0.625

4 0
3 years ago
Marcus designed a large salt-water aquarium in the shape of a rectangular prism. The aquarium has a width of x feet. The length
Valentin [98]

Answer:

2

Step-by-step explanation:

Took the test.

7 0
3 years ago
Find the<br> percent of change.<br> 35 pounds to 42 pounds
muminat

Answer:

I think it is 20%.

Step-by-step explanation:

35 * 0.2 = 7

35 + 7 = 42

4 0
3 years ago
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