You'd have no problem simplifying that expression if it said
-(5 cows) - (1 cow) + ( 14 cows) - (3 cows) .
You'd just add up the cows, and simplify the expression to say
5 cows .
When you see an expression that talks about 'x's instead of cows,
you get scared. It has something to do with algebra and math and
all that stuff, so you freeze.
Relax. Just make each 'x' a cow, and suddenly it almost solves itself.
Answer:
H
Step-by-step explanation:
given y = -x² + 3x.
let f(x) be y.
f(-2) = -(-2)² + 3(-2) = -10
f(-1) = -(-1)² + 3(-1) = -4
f(0) = -(0)² + 3(0) = 0
f(1) = -(1)² + 3(1) = 2
f(2) = -(2)² + 3(2) = 2
That is expanded if im not mistaken LEL
Answer:
The answer is below
Step-by-step explanation:
Let S denote syntax errors and L denote logic errors.
Given that P(S) = 36% = 0.36, P(L) = 47% = 0.47, P(S ∪ L) = 56% = 0.56
a) The probability a program contains both error types = P(S ∩ L)
The probability that the programs contains only syntax error = P(S ∩ L') = P(S ∪ L) - P(L) = 56% - 47% = 9%
The probability that the programs contains only logic error = P(S' ∩ L) = P(S ∪ L) - P(S) = 56% - 36% = 20%
P(S ∩ L) = P(S ∪ L) - [P(S ∩ L') + P(S' ∩ L)] =56% - (9% + 20%) = 56% - 29% = 27%
b) Probability a program contains neither error type= P(S ∪ L)' = 1 - P(S ∪ L) = 1 - 0.56 = 0.44
c) The probability a program has logic errors, but not syntax errors = P(S' ∩ L) = P(S ∪ L) - P(S) = 56% - 36% = 20%
d) The probability a program either has no syntax errors or has no logic errors = P(S ∪ L)' = 1 - P(S ∪ L) = 1 - 0.56 = 0.44
Answer:
Step-by-step explanation:
50,000
I think
