Answer: 8.5%
7/82=0.0853
Multiply by 100 to get percentage
0.0853 x 100 = 8.53
Based on the central angle theorem, the measure of angle AEB is: 140°.
<h3>What is the Central Angle Theorem?</h3>
According to the central angle theorem, the measure of an intercepted arc = measure of the central angle.
Arc AB = 140° [intercepted arc]
Angle AEB is the central angle.
Thus, based on the central angle theorem, the measure of angle AEB is: 140°.
Learn more about the central angle theorem on:
brainly.com/question/5436956
#SPJ1
<u>Given</u> -
- Area of rectangular field = Area of square field
- side of square = 60m
- breadth of the rectangular field = 32m
<u>To find</u> -
- length of the rectangular field
<u>Solution</u> -
Area of square = side × side = (60 × 60)m² =
Area of square =3600m²
Hence,
Area of rectangular field = Area of square field = 3600m²
Area of rectangular field = l × b = 3600m²
=> l × 32m = 3600m²
=> l = 
=> l = 112.5m
so, the length = 112.5m
Answer:
D
Step-by-step explanation:
Using the Cosine rule to find AC
AC² = BC² + AB² - (2 × BC × AB × cosB )
= 18² + 12² - ( 2 × 18 × 12 × cos75° )
= 324 + 144 - 432cos75°
= 468 - 111.8
= 356.2 ( take the square root of both sides )
AC =
≈ 18.9
-----------------------------------------
Using the Sine rule to find ∠ A
=
( cross- multiply )
18.9 sinA = 18 sin75° ( divide both sides by 18.9 )
sinA =
, then
∠ A =
(
) ≈ 66.9°
Answer:
a) 0.283 or 28.3%
b) 0.130 or 13%
c) 0.4 or 40%
d) 30.6 mm
Step-by-step explanation:
z-score of a single left atrial diameter value of healthy children can be calculated as:
z=
where
- X is the left atrial diameter value we are looking for its z-score
- M is the mean left atrial diameter of healthy children (26.7 mm)
- s is the standard deviation (4.7 mm)
Then
a) proportion of healthy children who have left atrial diameters less than 24 mm
=P(z<z*) where z* is the z-score of 24 mm
z*=
≈ −0.574
And P(z<−0.574)=0.283
b) proportion of healthy children who have left atrial diameters greater than 32 mm
= P(z>z*) = 1-P(z<z*) where z* is the z-score of 32 mm
z*=
≈ 1.128
1-P(z<1.128)=0.8703=0.130
c) proportion of healthy children have left atrial diameters between 25 and 30 mm
=P(z(25)<z<z(30)) where z(25), z(30) are the z-scores of 25 and 30 mm
z(30)=
≈ 0.702
z(25)=
≈ −0.362
P(z<0.702)=0.7587
P(z<−0.362)=0.3587
Then P(z(25)<z<z(30)) =0.7587 - 0.3587 =0.4
d) to find the value for which only about 20% have a larger left atrial diameter, we assume
P(z>z*)=0.2 or 20% where z* is the z-score of the value we are looking for.
Then P(z<z*)=0.8 and z*=0.84. That is
0.84=
solving this equation for X we get X=30.648