Okay,
so first you gotta know that cos(90-x) is equal to sinx and sin(90-x) is equal to cosx!!
Now all you gotta do is replace the cos(90-x) to sinx in the numerator and sin(90-x) to cosx in the denomenator inorder to make the numerator all into sin and denomenator all into cos.
After that, open up the brackets and solve...
At the end you'll hopefully get something like this :( 1+sin90 ÷ 1+cos90 )
And since sin90 is 1 (put it in the calculator!) and cos90 is 0, you'll get 2÷1 which is equals to 2!!
Hope this helped! :)
Answer:
I will comment the answer
Step-by-step explanation:
It will take a hour to answer your question
Answer:
i) 3*m*n + 7
Then we can write the first term as:
"3 times the product between two numbers"
Where the product of two numbers is m*n
And after that we need to add 7, then the complete sentence is:
"3 times the product between two numbers, increased by 7"
ii) x*y + (x + y)
The first part, x*y, can be written as:
"the product of two numbers"
where the two numbers are the number x and the number y.
After that, we add the sum of these two numbers, then the complete sentence can be:
"the product of two numbers, plus the sum of these two numbers"
I think the answer would be 4n
Answer:
BRUH I DONT KNOW
Step-by-s
4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) 4(5x−3)−3(4x−7) DO ALL OF THAT TO FIND THE ANSWER
