Question

What is the absolute value of the complex number -4- sqrt 2i? A) sqrt 14 B) 3sqrt2 C)14 D)18

Answer 1

Remember the pythagorean theorem.

a^2 + b^2 = c^2

The complex number is a+bi,  the absolute value is 'c'

$|-4-\sqrt{2} i| = \sqrt{(-4)^2 + (-\sqrt{2})^2} = \sqrt{16+2} = \sqrt{18} = 3\sqrt{2}$